<span>(a) The balanced equation shows that 2 moles of water result from 5 moles of
oxygen that reacts, so that is 0.4 times as many moles of water as O2. So if we
have 2.50 moles of oxygen reacting, we produce 0.4 times that amount, or
1.0 mole of water.
(b) The molecular weight of acetylene is 26 and that of O2 is 32, so we can set
up the proportion: 2.25 gm. / 52 = x gm. / 160
Then x grams = (2.25)(160) / 52 = 6.923 grams of O2 are required.
(c) The balanced equation shows that twice as many moles of CO2 are produced
as we have acetylene reacting. If 78.0 grams of acetylene react, that is 3 moles
so we produce twice that, or 6 moles of CO2. The molecular weight of CO2 is 44,
so we have 44 times 6, or 264 grams of carbon dioxide produced.
(d) If we collect 186 grams of CO2, the percentage yield is:
186/264 = 0.7045, or 70.45 percent yield.
Whew! Hope this answers all parts of your question!</span><span>
</span>
I would say that the answer is d?
Answer:
One nucleophilic center
Explanation;
Nucleophile:
Nucleophile is a substance which is nucleus loving in nature (<em>Nucleo</em>; Nucleus , <em>phile</em>; Loving). It is known as a specie which donates a lone pair of electrons to electrophile (electron loving) in a chemical reaction.
Thus, Nucleophile is the region of higher electron density in a molecule and attacks on the lower electron density region of another molecule. Also, the nucleophile can also contain a negative charge.
Number of Nucleophilic centers in Methanol:
The chemical structure of Methanol is attached below and it can be observed that the oxygen atom is containing two lone pair of electrons. Hence, the oxygen atom can act as a nucleophilic center. Therefore, there is only one nucleophilic center in methanol.
H₃C-OH + H₃C-Br → H₃C-O-CH₃ + HBr
In above reaction methanol is acting as a nucleophile and is attacking on electrophilic center (Carbon) of methyl bromide yielding dimethyl ether.
Answer:
The chemical equation by putting, a 2 on C₅H₁₂O, 15 on O₂, 10 on CO₂ , and 12 on H₂O in the equation;
2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O
Explanation:
- Chemical equations are balanced by putting coefficients on the reactants and products to ensure the total number of atoms on the left side equal to those on the right side.
- Balancing chemical equations is done to make chemical equations obey the law of conservation of mass.
- According to the law of conservation of mass, the mass of the reactants should always be equal to the mass of products.
- This is done by balancing chemical equations to ensure the total number of atoms on the left side is equal to that on the right side.
- Therefore, the balanced equation is;
2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O
