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r-ruslan [8.4K]
2 years ago
13

A calorimeter holds 50 g water at 22.0°C. A sample of hot iron is added to the water. The final temperature of the water and iro

n is 28.0°C. What is the change in enthalpy associated with the change in the water’s temperature?
Note: The specific heat of water is 4.18 J/°C

Use the formula ΔH = - cmΔT
Chemistry
1 answer:
makkiz [27]2 years ago
7 0

The change in enthalpy associated with the change in the water’s temperature is 1254 J.

<h3>What is specific heat?</h3>

The amount of heat required to increase the temperature of one gram of a substance by one Celsius degree is known as specific heat.

Enthalpy change will be calculated as:

ΔH = -cmΔT, where

m = mass of water = 50g

c = specific heat of water = 4.18J/g°C

ΔT = change in temperature = 28 - 22 = 6 °C

On putting values in the above equation, we get

ΔH = -(4.18)(50)(6) = -1254 J

Hence change in enthalpy of the reaction is -1254 J.

To know more about enthalpy change, visit the below link:

brainly.com/question/11628413

#SPJ1

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