<em> 7850 ft²</em>
- Step-by-step explanation:
<em>Hi there ! </em>
<em>d = 2r => r = d/2 = 100ft/2 = 50 feet</em>
<em>A = πr² </em>
<em>= 3.14×(50ft)² </em>
<em>= 3.14×2500ft²</em>
<em>= 7850 ft²</em>
<em>Good luck !</em>
Answer: 0.999986176
Step-by-step explanation:
To solve this, the probability distribution formula for selection will be used
Where P(x=r) = nCr * p^r * q^n-r
To get the probability that all 3cans are not overfilled, since the probability of success given in the question is that of a can being overfilled, then we will first derive the probability of having exactly 3cans being overfilled and subtract this gotten answer from 1
n= 3, r=3, p=0.024, q=1-0.024=0.976
When, 3 cans are overfilled, P(x=3) becomes:
P(x=3) = 3C3 * 0.024^3 * 0.976^0
P(x=3) = 1 * 0.000013824 * 1
P(x=3) = 0.000013824.
Then, probability that all three cans are not overfilled becomes :
1 - 0.000013824. = 0.999986176,
Step-by-step explanation:
The number which is repeated more times will be mode...
So...
11 is Answer
Answer:
x = 4 + sqrt(38) or x = 4 - sqrt(38)
Step-by-step explanation using the quadratic formula:
Solve for x over the real numbers:
2 (x^2 - 8 x - 22) = 0
Divide both sides by 2:
x^2 - 8 x - 22 = 0
x = (8 ± sqrt((-8)^2 - 4 (-22)))/2 = (8 ± sqrt(64 + 88))/2 = (8 ± sqrt(152))/2:
x = (8 + sqrt(152))/2 or x = (8 - sqrt(152))/2
sqrt(152) = sqrt(8×19) = sqrt(2^3×19) = 2sqrt(2×19) = 2 sqrt(38):
x = (2 sqrt(38) + 8)/2 or x = (8 - 2 sqrt(38))/2
Factor 2 from 8 + 2 sqrt(38) giving 2 (sqrt(38) + 4):
x = 1/22 (sqrt(38) + 4) or x = (8 - 2 sqrt(38))/2
(2 (sqrt(38) + 4))/2 = sqrt(38) + 4:
x = sqrt(38) + 4 or x = (8 - 2 sqrt(38))/2
Factor 2 from 8 - 2 sqrt(38) giving 2 (4 - sqrt(38)):
x = 4 + sqrt(38) or x = 1/22 (4 - sqrt(38))
(2 (4 - sqrt(38)))/2 = 4 - sqrt(38):
Answer: x = 4 + sqrt(38) or x = 4 - sqrt(38)