First angle to the right inside the triangle can be 60
Other angle inside the triangle can be 40
The upper angle outside the triangle 80
The last angle 100
Answer: For the first option it is 28y^2 +31y - 10
Step-by-step explanation: Hope this helps
Answer:
0
Step-by-step explanation:
Answer:
[(x + 6), (y + 1)]
Step-by-step explanation:
Vertices of the quadrilateral ABCD are,
A → (-5, 2)
B → (-3, 4)
C → (-2, 4)
D → (-1, 2)
By reflecting the given quadrilateral ABCD across x-axis to form the image quadrilateral A'B'C'D',
Rule for the reflection of a point across x-axis is,
(x, y) → (x , -y)
Coordinates of the image point A' will be,
A(-5, 2) → A'(-5, -2)
From the picture attached, point E is obtained by translation of point A'.
Rule for the translation of a point by h units right and k units up,
A'(x+h, y+k) → E(x', y')
By this rule,
A'(-5 + h, -2 + k) → E(1, -1)
By comparing coordinates of A' and E,
-5 + h = 1
h = 6
-2 + k = -1
k = 1
That means
Rule for the translation will be,
[(x + 6), (y + 1)]
The correct answer is -78.15 m.
Hope this helped! :)
