All categories

3 years ago

IM STRUGGLING HELP What is the equation of the line in the form y=Mx+b

Mathematics

1 answer:

Andrej [43]3 years ago

5 0

y=3x+6

Step-by-step explanation:

point 1 (2;12)

point 2 (4;18)

$m = \frac{y2 - y1}{x2 - x1}$

$m = \frac{18 - 12}{4 - 2}$

$m = \frac{6}{2}$

m=3

y=mx+b

sub in a point and gradient

12=3(2)+b

12=6+b

b=6

y=3x+6

You might be interested in

What is the volume of the cone with diameter 6 m abd height 5 m? Express your answers in terms of pi.

Margaret [11]

Answer:

Step-by-step explanation:

The formula for calculating the volume (V) of a cone is

V = $\frac{1}{3}$ πr²h

where r is the radius of the base and h is the height

here r = $\frac{6}{2}$ = 3 and h = 5

V = $\frac{1}{3}$ π × 3² × 5

= $\frac{1}{3}$ π × 9 × 5 = 15π m³ → B

8 0

4 years ago

Simplify the expression 6 + 5x - (-3x)

DanielleElmas [232]

Answer:

= 6+8x

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Jennifer was asked to rewrite each of the following expressions in word form, using the words sum, product, difference, and quot

Strike441 [17]

So,

We just have to substitute the appropriate words for the operations and grouping symbols.

A. Twenty times the quantity of the difference between y and 3.

B. The sum of the quotient of x and 9, and 5

6 0

3 years ago

Find the curl and the divergence of the vector field f(x, y, z) = x2yz i + xy2z j + xyz2 k

xxTIMURxx [149]

$\mathbf f(x,y,z)=x^2yz\,\mathbf i+xy^2z\,\mathbf j+xyz^2\,\mathbf k$

$\mathrm{div}\mathbf f(x,y,z)=\dfrac{\partial(x^2yz)}{\partial x}+\dfrac{\partial(xy^2z)}{\partial y}+\dfrac{\partial(xyz^2)}{\partial z}$
$=2xyz+2xyz+2xyz$
$=6xyz$

$\mathrm{curl}\mathbf f(x,y,z)=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\\\\frac\partial{\partial x}&\frac\partial{\partial y}&\frac\partial{\partial z}\\\\x^2yz&xy^2z&xyz^2\end{vmatrix}$
$=\left(\dfrac{\partial(xyz^2)}{\partial y}-\dfrac{\partial(xy^2z)}{\partial z}\right)\,\mathbf i-\left(\dfrac{\partial(xyz^2)}{\partial x}-\dfrac{\partial(x^2yz)}{\partial z}\right)\,\mathbf j+\left(\dfrac{\partial(xy^2z)}{\partial x}-\dfrac{\partial(x^2yz)}{\partial y}\right)\,\mathbf k$
$=\left(xz^2-xy^2\right)\,\mathbf i-\left(yz^2-x^2y\right)\,\mathbf j+\left(y^2z-x^2z\right)\,\mathbf k$

6 0

4 years ago

PLEASE ANSWER ASAPPP

Alex787 [66]

Answer:

No solution

Step-by-step explanation:

No solution because you cant add some of these numbers together and get that same answe

5 0

3 years ago