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Romashka-Z-Leto [24]
2 years ago
11

4. A bag contains five red marbles, two orange marbles, one yellow marble, and two green marbles. Two marbles are drawn from the

bag.
What is the approximate probability one of the chosen marbles is orange and one of the chosen marbles is green?
A. 0.02222
B. 0.04444
C. 0.08889
D. 0.13333
Mathematics
1 answer:
Vitek1552 [10]2 years ago
4 0

Answer:

  • C. 0.08889

Step-by-step explanation:

<u>Total number of marbles:</u>

  • 5 + 2 + 1 + 2 = 10

<u>There are two possibilities</u>

  • Orange then green or green the orange

<u>The probabilities are:</u>

  • P(o&g) = 2/10*2/9 = 2/45
  • P(g&o) =2/10*2/9 = 2/45

<u>Required probability is:</u>

  • P = 2/45*2 = 4/45 =  0.08889

Correct choice is C

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What is the value of x?<br> 40°<br> (6x + 2)
Anvisha [2.4K]

Answer:

x = 8

Step-by-step explanation:

40 + 6x + 2 = 90   {Complementary angles}

Combine like terms

40+ 2 + 6x = 90

     42 +6x = 90         {Subtract 42 form both sides}

             6x = 90 - 42

             6x = 48       {divide both sides by 6}

        6x/6 = 48/6

             x = 8

6 0
3 years ago
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X^3 plus 6x squared plus 3x minus−10x plus 5
Iteru [2.4K]
 the answer is X^3+6x<span>^2-7x+5

</span>
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3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
2 years ago
Convert the length 7 centimeters to meters. Compare the numerical values when both numbers are written in scientific notation
miv72 [106K]
<span>1.       </span><span>Given numbers
=> 7 centimeters convert to meters
In every 1 meter there are 100 centimeters
=> 7 / 100
=> 0.07
Therefore in 7 centimeters there are 0.07 meters.
7 cm is a whole number while 0.07 m is a decimal number
Scientific Notation of each numbers
=> 7 cm = 7 x 10^0
=> 7 m = 1 x 10^-2
Scientific notation by the way is an expression used by the scientist to make a large number or very small number easy to handle.


</span>



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Manny goes bowling.
ycow [4]
I believe the answer is B. Hope this helps :)
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