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Romashka-Z-Leto [24]
3 years ago
11

4. A bag contains five red marbles, two orange marbles, one yellow marble, and two green marbles. Two marbles are drawn from the

bag.
What is the approximate probability one of the chosen marbles is orange and one of the chosen marbles is green?
A. 0.02222
B. 0.04444
C. 0.08889
D. 0.13333
Mathematics
1 answer:
Vitek1552 [10]3 years ago
4 0

Answer:

  • C. 0.08889

Step-by-step explanation:

<u>Total number of marbles:</u>

  • 5 + 2 + 1 + 2 = 10

<u>There are two possibilities</u>

  • Orange then green or green the orange

<u>The probabilities are:</u>

  • P(o&g) = 2/10*2/9 = 2/45
  • P(g&o) =2/10*2/9 = 2/45

<u>Required probability is:</u>

  • P = 2/45*2 = 4/45 =  0.08889

Correct choice is C

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Answer:

\frac{1}{2} (a + 2b)(a - b)

Step-by-step explanation:

Assuming you require the expression to be factored

Given

\frac{1}{2} a² + \frac{1}{2} ab - b² ← factor out \frac{1}{2} from each term

= \frac{1}{2} (a² + ab - 2b²) ← factor the quadratic

Consider the factors of the coefficient of the b² term(- 2) which sum to give the coefficient of the ab- term (+ 1)

The factors are + 2 and - 1, since

2 × - 1 = - 2 and 2 - 1 = + 1, thus

a² + ab - 2b² = (a + 2b)(a - b) and

\frac{1}{2} a² + \frac{1}{2} ab - b² = \frac{1}{2}(a + 2b)(a - b)

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3 years ago
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Answer:

2.92 × 10⁹

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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