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kobusy [5.1K]
2 years ago
14

Find the total volume of the material used to making the cylinder​

Physics
1 answer:
gladu [14]2 years ago
4 0

Answer:

Hey mate

Explanation:

Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.

pls mark me as brainliest!!

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Bob is threatening Tom’s life with a giant laser with wavelength (650 nm), a distance (D = 10 m) from the wall James is shackled
Fittoniya [83]

Answer:

He should stand from the center of laser pointed on the wall at 1.3 m.

Explanation:

Given that,

Wave length = 650 nm

Distance =10 m

Double slit separation d = 5 μm

We need to find the position of fringe

Using formula of distance

d\sin\theta=n\lambda

d\dfrac{y}{D}=n\lambda

y=\dfrac{\lambda D}{d}

Put the value into the formula

y=\dfrac{650\times10^{-9}\times10}{5\times10^{-6}}

y=1.3\ m

Hence, He should stand from the center of laser pointed on the wall at 1.3 m.

8 0
3 years ago
Which planet, when viewed through a telescope, appears as a reddish ball interrupted by some permanent dark regions that change
Andrej [43]
The answer should be Mars. 
4 0
3 years ago
Read 2 more answers
Which term defines seeking some way of achieving a goal by overcoming obstacles or finding an answer to a question?
irga5000 [103]

Answer:

Problem solving

hope this helps :)

8 0
3 years ago
Andrea's near point is 20.0 cm and her far point is 2.0 m. Her contact lenses are designed so that she can see objects that are
Shalnov [3]

Answer:

the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

Explanation:

Given the data in the question,

near point = 20 cm

far point = 2 m = 200 cm

Now, for an object that is infinitely far away, the image is at is its far point.

so using the following expression, we can determine the focal length

1/f = 1/i + 1/o

where f is the focal length, i is the image distance and o is the object distance.

here, far point i = 2 m = 200 cm  and v is ∞

so we substitute

1/f = 1/(-200 cm)  +  1/∞

f = -200 cm

Also, for object at its closest point, the image appear at near point,

so

1/f = 1/i + 1/o

we make o the subject of formula

o = ( i × f ) / ( i - f )

given that near point i = 20 cm

we substitute

o = ( -20 × -200 ) / ( -20 - (-200) )

o = 4000 / 180

o = 22.2 cm

Therefore, the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

4 0
3 years ago
If a quasar is moving away from us at v/c = 0.8, what is the measured redshift?
Delicious77 [7]

Answer:

The measured redshift is z =2

Explanation:

Since the object is traveling near light speed, since v/c = 0.8, then we have to use a redshift formula for relativistic speeds.

z= \sqrt{\cfrac{c+v}{c-v}}-1

Finding the redshift.

We can prepare the formula by dividing by lightspeed inside the square root to both numerator and denominator to get

z= \sqrt{\cfrac{1+\cfrac vc}{1-\cfrac vc}}-1

Replacing the given information

z= \sqrt{\cfrac{1+0.8}{1-0.8}}-1

z= \sqrt{\cfrac{1.8}{0.2}}-1\\z= \sqrt{9}}-1\\z=3-1\\z=2

Thus the measured redshift is z = 2.

4 0
3 years ago
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