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Angelina_Jolie [31]
2 years ago
12

if a certain star emits most intensely in the visible region of the spectrum, a cooler star would emit mostly in what part of th

e spectrum
Physics
1 answer:
ioda2 years ago
7 0

A cooler star would emit mostly in infrared range of the spectrum.

<h3>Emission of high temperature stars</h3>

High temperature stars like the Sun, which are approximately 6000 K at the surface, emit most of their radiation at visible wavelengths.

<h3>Emission of the cooler stars</h3>

In stark contrast to high temperature stars, the cooler stars emit most of their radiations in the infrared (IR) range.

Thus, we can conclude that,  a cooler star would emit mostly in infrared range of the spectrum.

Learn more about emission of stars here: brainly.com/question/1287536

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You have a grindstone (a disk) that is 95.2 kg, has a 0.399 m radius, and is turning at 93 rpm, and you press a steel axe agains
olya-2409 [2.1K]

Answer:

angular acceleration is -0.2063  rad/s²

Explanation:

Given data

mass m = 95.2 kg

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kinetic coefficient of friction  μ = 0.2

to find out

angular acceleration

solution

we know frictional force that is = radial force × kinetic coefficient of friction

frictional force = 19.6 × 0.2

frictional force = 3.92 N

and

we know moment of inertia  that is

γ =  I ×α = frictional force × r

so

γ  = 1/2 mr²α

α  = -2f /mr

α  = -2(3.92) /95.2 (0.399)

α  = - 7.84 / 37.9848 = -0.2063

so angular acceleration is -0.2063  rad/s²

3 0
3 years ago
Nalah labels ten rats with the numbers 1 through 10. Then, she records how long it takes each rat to run through a maze. She fin
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Answer:

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Explanation:

5 0
3 years ago
Is friction and pushing similar ????
olya-2409 [2.1K]

Answer:

Yes, they are.

Explanation:

3 0
3 years ago
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I have 2 bulbs one coverts 60% of energy to light 45% which is the most efficient and what happens to the rest of the energy
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Answer:

The first one (60%)

Explanation:

The first one converts 15% more energy than the other one. Therefore, it is more efficient.

Hope this helps!

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