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Vedmedyk [2.9K]
2 years ago
6

If a ball is tossed straight up into the air, at what position is its potential energy the greatest? Question 3 options: When it

begins to fall back to your hand when it approaches the top of its flight when it reaches the top of its flight when it first leaves your hand.
Physics
1 answer:
Gennadij [26K]2 years ago
7 0

The ball has the greatest potential energy when it reaches the top of its flight. Option C is correct.

<h3>What is potential energy?</h3>

The potential energy of a body or object is due to its position. The ball has the greatest potential energy when it reaches the highest point.

U = mgh

Where,

U - potential energy

m - mass

g - gravitation acceleration

h - height

Since the mass and gravitation acceleration is constant hence potential energy will be directly proportional to the height of the ball.

Therefore, the ball has the greatest potential energy when it reaches the top of its flight.

Learn more about potential energy:

brainly.com/question/1250558

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What is the net force of an object with a mass of 90.0 and accelerating at 3.0 m/s
Ksivusya [100]

The net force is 270 N

Explanation:

We can solve this problem by using Newton's second law, which states that the net force on an object is equal to the product between its mass and its acceleration:

F=ma

where

F is the force

m is the mass

a is the acceleration

In this problem, we have

m = 90.0 kg

a=3.0 m/s^2

Substituting, we find the net force on the object:

F=(90.0)(3.0)=270 N

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

3 0
3 years ago
A motorcycle starts from rest and has a constant acceleration. In a time interval t, it undergoes a displacement x and attains a
iren [92.7K]

Answer:

√(6ax)

Explanation:

Hi!

The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:

x=(1/2)at^2

Then the we need to find the time t' for which the displacement is 3x

3x=(1/2)a(t')^2

Solving for t':

t'=√(6x/a)

Now, the velocity of the motorcycle as a function of time is:

v(t)=a*t

Evaluating at t=t'

v(t')=a*√(6x/a)=√(6*x*a)

Which is the final velocity

Have a nice day!

3 0
3 years ago
Please help!!! 50 POINTS
taurus [48]

Answer:

The Energy Involved In A Reaction That Changes Methane Gas And Oxygen Into Carbon Dioxide And Water.

Explanation:

6 0
3 years ago
Read 2 more answers
Find the temperature
mote1985 [20]

Where is the Temperature bud?

5 0
3 years ago
Read 2 more answers
3. A concrete highway is built of slabs 12 m long (20o C). How wide should the expansion cracks between the slabs be (at 20o C)
lesantik [10]

Answer:

\Delta x=2.304\times 10^{-2}\ m=2.304\ cm is the minimum gap between the slabs

Explanation:

Given:

  • length of the concrete highway, l=12\ m
  • coefficient of thermal expansion, \alpha=12\times 10^{-6}\ ^{\circ}C^{-1}
  • range of temperature variation, (-30^{\circ}C\ to\ 50^{\circ}C) \Rightarrow \Delta T=80^{\circ}C

<u>Now form the equation of thermal expansion:</u>

\Delta l=l\times \alpha\times \Delta T

\Delta l=12\times (12\times 10^{-6})\times 80

\Delta l=1.152\times 10^{-2}\ m

Since each slab of the highway expands by the above length so the minimum gap between the slabs to prevent buckling:

\Delta x=2\times \Delta l

\Delta x=2\times( 1.152\times 10^{-2})

\Delta x=2.304\times 10^{-2}\ m=2.304\ cm is the minimum gap between the slabs

4 0
3 years ago
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