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Vedmedyk [2.9K]
2 years ago
6

If a ball is tossed straight up into the air, at what position is its potential energy the greatest? Question 3 options: When it

begins to fall back to your hand when it approaches the top of its flight when it reaches the top of its flight when it first leaves your hand.
Physics
1 answer:
Gennadij [26K]2 years ago
7 0

The ball has the greatest potential energy when it reaches the top of its flight. Option C is correct.

<h3>What is potential energy?</h3>

The potential energy of a body or object is due to its position. The ball has the greatest potential energy when it reaches the highest point.

U = mgh

Where,

U - potential energy

m - mass

g - gravitation acceleration

h - height

Since the mass and gravitation acceleration is constant hence potential energy will be directly proportional to the height of the ball.

Therefore, the ball has the greatest potential energy when it reaches the top of its flight.

Learn more about potential energy:

brainly.com/question/1250558

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A washing machine heats 10kg of water in each wash cycle. How much energy is saved by washing at 30'c instead of 50'c if the sta
Volgvan
The equation for this is very simple you add then you subtract then you get the answer then you divide then it all works out for you
6 0
3 years ago
Some lenses are shaped with one flat side and one spherically-shaped side. This shape is designed to focus parallel light rays o
Komok [63]

Answer:

Some lenses are used to focus light to a pre-defined point based on the amount of curvature of their surfaces.

In a piano design convex, some surfaces are flat while others has positive lenses (biconvex)

Explanation:

Solution

These lenses are applied to pay attention to light in a  point pre-defined  based on the amount of curvature of their surfaces.

For that of a plano-convex design, one surface has a positive curve and for biconvex lenses, both surfaces are positively curved while the other  remains flat.

when used practically, plano-convex lenses are most commonly used where the object being imaged is far apart from lens.

7 0
3 years ago
In a closed energy system, energy is?​
Alisiya [41]

Answer:

Explanation:

A closed system can exchange energy but not matter, with its surroundings. An isolated system cannot exchange any heat, work, or matter with the surroundings, while an open system can exchange energy and matter.

Hope this helped you!

3 0
2 years ago
An open pipe of length 0.39m vibrates in the third harmonic with a frequency of 1400Hz. What is the distance from the center of
Gnoma [55]

Length of the pipe = 0.39 m

Third harmonic frequency = 1400 Hz

For the third harmonic:

Wavelength = \frac{2L}{3}

The center of the open pipe will host a node and the nearest anti - node from the center will be at the 0.25 × wavelength

Distance from center  = 0.25 × wavelength

Distance = 0.25 x \frac{2L}{3}

Plugging the value of the length of the pipe (L) = 0.39 m = 39 cm

Distance = 0.25 x \frac{2 \times 39}{3}

Distance from the center to the nearest anti - node = 6.5 cm

Hence, the nearest distance to the anti - node from the center = 6.5 cm

So, option C is correct.

7 0
3 years ago
How can i find the acceleration?(rope and grinder have no weight) *** sorry for my english
Finger [1]
The main formula to be used here is

                       Force = (mass) x (acceleration).

We'll get to work in just a second.  But first, I must confess to you that I see
two things happening here, and I only know how to handle one of them.  So
my answer will be incomplete, but I believe it will be more reliable than the
first answer that was previously offered here.

On the <u>right</u> side ... where the 2 kg and the 3 kg are hanging over the same
pulley, those weights are not balanced, so the 3 kg will pull the 2kg down, with
some acceleration.  I don't know what to do with that, because . . .

At the <em>same time</em>, both of those will be pulled <u>up</u> by the 10 kg on the other side
of the upper pulley.

I think I can handle the 10 kg, and work out the acceleration that IT has.

Let's look at only the forces on the 10 kg:

-- The force of gravity is pulling it down, with the whatever the weight of 10 kg is.

-- At the same time, the rope is pulling it UP, with whatever the weight of 5 kg is ...
that's the weight of the two smaller blocks on the other end of the rope. 

So, the net force on the 10 kg is the weight of (10 - 5) = 5 kg, downward.

The weight of 5 kg is (mass) x (gravity) = (5 x 9.8) = 49 newtons.

The acceleration of 10 kg, with 49 newtons of force on it, is

     Acceleration = (force) / (mass) = 49/10 = <em>4.9 meters per second²</em>
7 0
3 years ago
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