If a ball is tossed straight up into the air, at what position is its potential energy the greatest? Question 3 options: When it
1 answer:
The ball has the greatest potential energy when it reaches the top of its flight. Option C is correct.
<h3>What is potential energy?</h3>The potential energy of a body or object is due to its position. The ball has the greatest potential energy when it reaches the highest point.
Where,
- potential energy
- mass
- gravitation acceleration
- height
Since the mass and gravitation acceleration is constant hence potential energy will be directly proportional to the height of the ball.
Therefore, the ball has the greatest potential energy when it reaches the top of its flight.
Learn more about potential energy:
You might be interested in
force of friction on the cart is given as
here we also know the reaction force due to surface
so we can say reaction force is given as
now by force balance we will say
also we know that
now minimum force required to set this into motion
here we know that
So it will require 259 N minimum force to move it
According to the law of conservation of momentum:
m1 = mass of first object
m2 = mass of second object
v1 = Velocity of the first object before the collision
v2 = Velocity of the second object before the collision
v'1 = Velocity of the first object after the collision
v'2 = Velocity of the second object after the collision
Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know.
m1 = 125 kg v1 = 12m/s v'1 = -12.5m/s
m2 = 235kg v2 = -13m/s v'2 = ?
Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation.
The velocity of the 2nd car after the collision is 0.03m/s.
m1 = mass of first object
m2 = mass of second object
v1 = Velocity of the first object before the collision
v2 = Velocity of the second object before the collision
v'1 = Velocity of the first object after the collision
v'2 = Velocity of the second object after the collision
Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know.
m1 = 125 kg v1 = 12m/s v'1 = -12.5m/s
m2 = 235kg v2 = -13m/s v'2 = ?
Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation.
The velocity of the 2nd car after the collision is 0.03m/s.