Answer:
· This image may result from the construction of <em>an angle congruent to a given angle</em>.
· The next step in this construction is to set the compass width to <em>arc JK and draw an arc centered at L intersecting the existing arc through L</em>.
Step-by-step explanation:
If the step shown above results in point of intersection P, and the construction is completed by drawing ray DP, then this construction produces triangle DLP congruent to triangle BKJ. The angle at D will be congruent to the angle at B because CPCTC. Hence an angle congruent to a given angle will have been constructed.
Answer:
The equation that represents this situation is 2c² - 5c - 322 = 0
Step-by-step explanation:
∵ Kenan has c clients
∵ Jeff has five less than twice the number of clients that
Kenan has
- That means multiply c by 2 and then subtract 5 from the
product to find the number of Jeff's clients
∴ Jeff's clients = 2c - 5
∵ The product of the number of clients they have is 322
∴ c × (2c - 5) = 322
- Multiply c by the bracket (2c - 5)
∴ (c)(2c) + (c)(-5) = 322
∴ 2c² + (-5c) = 322
- Remember (+)(-) = (-)
∴ 2c² - 5c = 322
- Subtract 322 from both sides
∴ 2c² - 5c - 322 = 0
The equation that represents this situation is 2c² - 5c - 322 = 0
:
he graph shows one of the linear equations for a system of equations. Which equation represents the second linear equation for the
system of equations that has the solution which corresponds to a point at (12, -39)
Answer:
the correct answer is C
Step-by-step explanation:
So first we want to find how far away they were after one hour.
Assuming they were going at a steady rate:
Since:
320 miles = distance traveled in 2 hours
We can divide both sides by 2 to get:
160 miles = distance traveled in 1 hour.
So we now know that the trains were 160 miles apart after 1 hour.
So we can assign the eastbound train a variable for its speed right now, or just x. And then the westbound train would be x + 18.
So, since the rate is in miles per hour, and they traveled 160 miles in one hour, we can say:
x + x + 18 = 160 miles
Then just solve.
2x + 18 = 160
-18 -18
2x = 142
/2 /2
x = 71
Since x equals the rate of the eastbound train, and we're looking for the westbound train, just add 18 to 71 because the westbound train was going 18 mph faster than the eastbound train.
18 + 71 = 89
So the rate of the westbound train is 89 mph.
