Evaluate the definite integral. 1 3ti + 7t3j + 3 t k dt âˆ’1

1 answer:

8 0

It would be so much clearer if you'd please put parentheses around the t-functions:

Evaluate the definite integral. (1/3)t i + (7t)^3 j + (3t) k dt

Also , there should be a set of brackets or parentheses around

(1/3)t i + (7t)^3 j + (3t) k. And, finally, we need an explanation of your âˆ’1. I do not recognize it at all.

To find the indefinite integral of [ (1/3)t i + (7t^3) j + (3t) k ]dt
integrate term by term:

(1/3)(t^2)/2) i + 7*t^4/3 j + (3*t^2/2) k + c

You might be interested in

Simplify. -3(2x - 2) + 4 pls and thank you

Mila [183]

-6x+10 would be ur answer :)

5 0

3 years ago

Read 2 more answers

Convert the fraction 7 24 into a repeating decimal.

goldenfox [79]

$\dfrac7{24}=\dfrac6{24}+\dfrac1{24}=\dfrac14+\dfrac1{24}$

$\dfrac1{24}=\dfrac1{8\time3}=\dfrac a8+\dfrac b3=\dfrac{3a+8b}{24}$
$\implies3a+8b=1$

We can choose $a=-1$ and $b=\dfrac12$ , so that

$\dfrac1{24}=-\dfrac18+\dfrac16$

Recalling that $\dfrac13=0.333\ldots$ , it follows that $\dfrac16=0.166\ldots$ . So,

$\dfrac1{24}=0.125+0.166\ldots=0.04166\ldots$
$\implies\dfrac7{24}=0.25+0.4166\ldots=0.29166\ldots$