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3 years ago

8

PLEASE HELP find mQT and m

1 answer:

Reika [66]3 years ago

4 0

Answer:

$.x1 - 4 { {0.36 + + \times 4xx { {052. < < }^{?} }^{2} }^{?} } \gamma eee}$

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A parallelogram has two

Hatshy [7]

Answer:

x + (x + 55) = 180

2x =125

The angle is 62.5 degrees

Double-Check

62.5 + (62.5 + 55) = 180

125 + 55 = 180

62.5 is the smaller angle

Step-by-step explanation:

6 0

3 years ago

X is less than or equal to 2 Write in interval notation.

Talja [164]

X is less than -2, so -2 is our largest value of the interval, so it goes on the right. Since there is no lower endpoint (it is ALL values less than -2), we put the negative infinity symbol on the left side. The curved end on -2 indicates an open interval

3 0

3 years ago

A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?

kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

$f(x)=\frac{1}{2^{2x}}$ (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

$\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]$ (2)

To solve this derivative you use the following derivative formula:

$\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}$

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

$\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)$

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

$-2(ln2)2^{-2x}=-1$

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

$-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235$

With this value you calculate f(a):

$f(a)=\frac{1}{2^{2(0.235)}}=0.721$

Next, you use the general equation of line:

$y-y_o=m(x-x_o)$

for xo = a = 0.235 and yo = f(a) = 0.721:

$y-0.721=(-1)(x-0.235)\\\\y=-x+0.956$

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

$0=-x+0.956\\\\x=0.956$

hence, the x-intercept of the tangent line is 0.956

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3 years ago

У— пинь<br> 7.<br> Graph y= 4x-3

Nat2105 [25]

Answer:

какие?

Step-by-step explanation:

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3 years ago

Write an addition equation that is represented by the model below.

katrin2010 [14]

Answer:

Step-by-step explanation:

Okay I'm not sure but I found an article online that seemed explanatory so here ya go

6 0

4 years ago