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3 years ago

PLEASE HELP find mQT and m

Mathematics

1 answer:

Reika [66]3 years ago

4 0

Answer:

$.x1 - 4 { {0.36 + + \times 4xx { {052. < < }^{?} }^{2} }^{?} } \gamma eee}$

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What is the estimate of 979

saw5 [17]

I'm pretty sure that it would be 1,000...

4 0

4 years ago

Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1

Shkiper50 [21]

Answer:

$\displaystyle -\frac{1}{2} \leq x < 1$

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

$\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0$

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

$\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0$

Simplifying by x-1 and taking x=1 out of the possible solutions:

$\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0$

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

$(6x^3+14x^2+10x+12)$

is always positive and doesn't affect the result. It can be neglected. The expression

$(x-\frac{1}{2})^2$

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

$\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0$

For the expression to be negative, both signs must be opposite, that is

$(x+\frac{1}{2})\geq 0, (x-1)$

$(x+\frac{1}{2})\leq 0, (x-1)>0$

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

$\displaystyle -\frac{1}{2} \leq x < 1$

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

$\boxed{\displaystyle -\frac{1}{2} \leq x < 1 }$

7 0

3 years ago

A truck leaves point A traveling 60 mph. After 2 hours, a car leaves point A traveling 90 mph and follows the truck's route. At

lora16 [44]

Answer:

Step-by-step explanation:

3 0

3 years ago

Find the length of the missing side of the triangle below

True [87]

Answer:

x = 28.8

Step-by-step explanation:

Using the Sine rule in the triangle then

$\frac{43}{sin87}$ = $\frac{x}{sin42}$ ( cross- multiply )

x × sin87° = 43 × sin42° ( divide both sides by sin87° )

x = $\frac{43sin42}{sin87}$ = 28.8

5 0

4 years ago

I need the answers to <br> x, y, and m

professor190 [17]

Answer:

x= 79 y= 15 m=54

Step-by-step explanation:

both triangles are basically mirrored, so since x+11 is in the same position as angle H the real equation would be: x+11=90 and the same thing for y+7 because that side is the same as side FG the equation would be y+7=22. For M since angles E and H are 35 and 90 you just add them together and then subtract them from 180 because are triangles add up to 180 degrees in terms of angles not sides.

8 0

3 years ago

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