Answer:
a

b
![x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }](https://tex.z-dn.net/?f=x%28t%29%20%3D%20%20x_o%20e%5E%7B%5Cfrac%7B-%5Calpha%20y_o%20%7D%7B%5Cbeta%20%7D%5Be%5E%7B-%5Cbeta%20t%7D%20-%201%5D%20%7D)
c

Step-by-step explanation:
From the question we are told that

Now integrating both sides

Now taking the exponent of both sides

=> 
Let 
So

Now from the question we are told that

Hence

=> 
So

From the question we are told that

substituting for y

=> 
Now integrating both sides

Now taking the exponent of both sides

=> 
Let 
=> 
Now from the question we are told that

So

=> 
divide both side by 
=> 
So

=> 
=> ![x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }](https://tex.z-dn.net/?f=x%28t%29%20%3D%20%20x_o%20e%5E%7B%5Cfrac%7B%5Calpha%20y_o%20%7D%7B%5Cbeta%20%7D%5Be%5E%7B-%5Cbeta%20t%7D%20-%201%5D%20%7D)
Generally as t tends to infinity ,
tends to zero
so

Answer:
the statements are not equivalent
Answer:
162.5mi
Step-by-step explanation:
If the scale of the map is 1in:25mi, and you measure 6.5in between two twoms, then the real distance would be 6.5in*25mi = 162.5mi.
x =2 y =8
2x + 2y=20
2x=20-2y
x=10-y
Ahora len la otra ecuacion remplazamos x por (10-y)
-2(10-y)-6y=-52
-20+2y-6y=-52
2y-6y= -32 (-52+20= -32)
-4y=-32
-y=-8
y=8 x=10-y x=2
2*2+2*8=20
4+16=20
-2*2-6*8= -52
-4-48= -52