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Crank
4 years ago
13

Figure 1 is transformed to Figure 3, as shown in the diagram. Describe the transformation. A) dilation, then reflection B) refle

ction, then rotation C) rotation, then reflection D) translation, then rotation

Mathematics
2 answers:
Nataly_w [17]4 years ago
4 0

Answer:

The correct answer is C. Rotation, then reflection

Step-by-step explanation:

in the diagram 2, 3 are facing left and 14 should be facing right so if you rotate 1 and make it face left instead of right you get your answer


<h3>By the way i attached the file in the answer!! below |</h3><h3>                                                                                           |</h3><h3>                                                                                          V</h3>

tresset_1 [31]4 years ago
3 0
C. hope this helps...
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3 years ago
Which of these statements is best? The errors in a regression model are assumed to have an increasing mean. The regression model
frutty [35]

Answer:

\epsilon = Y -X\beta

And the expected value for E(\epsilon) = 0 a vector of zeros and the covariance matrix is given by:

Cov (\epsilon) = \sigma^2 I

So we can see that the error terms not have a variance of 0. We can't assume that the errors are assumed to have an increasing mean, and we other property is that the errors are assumed independent and following a normal distribution so then the best option for this case would be:

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Step-by-step explanation:

Assuming that we have n observations from a dependent variable Y , given by Y_1, Y_2,....,Y_n

And for each observation of Y we have an independent variable X, given by X_1, X_2,...,X_n

We can write a linear model on this way:

Y = X \beta +\epsilon

Where \epsilon_{nx1} i a matrix for the error random variables, and for this case we can find the error ter like this:

\epsilon = Y -X\beta

And the expected value for E(\epsilon) = 0 a vector of zeros and the covariance matrix is given by:

Cov (\epsilon) = \sigma^2 I

So we can see that the error terms not have a variance of 0. We can't assume that the errors are assumed to have an increasing mean, and we other property is that the errors are assumed independent and following a normal distribution so then the best option for this case would be:

The regression model assumes the errors are normally distributed.

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3 years ago
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