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WARRIOR [948]
3 years ago
5

What is the sqaure root of 10

Mathematics
2 answers:
Elodia [21]3 years ago
8 0

Answer:

3.16227766017

Step-by-step explanation:

Lady_Fox [76]3 years ago
7 0

Answer:

The square root of 10 is 3.162

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Which of the following values is a solution of |2-x| less than 4
morpeh [17]

The correct answer is -1.

In order to solve this, we need to split into the positive and negative version of the answers. Let's start with the positive version.

2 - x < 4

-x < 2

x > -2 ----> NOTE: When we divide by -1, we have to change the direction of the sign.

Now we'll do the negative version.

2 - x > -4

-x > -6

x < 6

So we know the number must be greater than -2, but less than 6. The only number on this list that fits that is -1.

4 0
3 years ago
given the following functions f(x) and g(x), solve (f g)(3) and select the correct answer below: f(x) = 6x 3 g(x) = x − 7 4 17 2
NeTakaya
Hello,
+++++++++++++++++++++++++++++++++++++++++
Thanks for the incorrect formula!
+++++++++++++++++++++++++++++++++++++++++
I have tested (fog)(x) ,(f*g)(x) and finally (f+g)(x)

f(x)=6x++++++++++++++++++++++++3
g(x)=x-7
(f+g)(x)=6x+3+x-7=7x-4
(f+g)(3)=7*3-4=17

Answer B
++++++++++++++++++++++++++++++++++++

3 0
3 years ago
Please help I’ll mark you as brainliest if correct!
Darya [45]

Answer:

A is 4

Step-by-step explanation:

A _ 8 _ _ _ _ _ _ _ _ 8 _ 6

A _ 8 _ _ _ _ _ _ _ _ 8 4 6

A _ 8 _ _ _ _ _ _ _ 6 8 4 6

A _ 8 _ _ _ _ _ _ 4 6 8 4 6

A _ 8 _ _ _ _ _ 8 4 6 8 4 6

A _ 8 _ _ _ _ 6 8 4 6 8 4 6

A _ 8 _ _ _ 4 6 8 4 6 8 4 6

A _ 8 _ _ 8 4 6 8 4 6 8 4 6

A _ 8 _ 6 8 4 6 8 4 6 8 4 6

A _ 8 4 6 8 4 6 8 4 6 8 4 6

A 6 8 4 6 8 4 6 8 4 6 8 4 6

4 6 8 4 6 8 4 6 8 4 6 8 4 6

A is 4

Hope this helps!

4 0
3 years ago
Read 2 more answers
Please help!!!<br> A. quadratic<br> B. none<br> C. linear<br> D. exponential
larisa86 [58]
The answer to this question is B, because neither of suggestsions make sense
3 0
3 years ago
Factorising quadratics<br><br> X squared + 5x -6<br> X squared - 2x15<br> X squared -7x +12
34kurt

Answer:

  • (x -1)(x +6)
  • (x -5)(x +3)
  • (x -4)(x -3)

Step-by-step explanation:

In each case, you're looking for divisors of the constant that have a sum equal to the x-coefficient. Those divisors are the constants in the binomial factors.

1) -6 = -1·6 = -2·3 . . . . . (-1)+(6) = 5, so these are the constants of interest.

  x^2 +5x -6 = (x -1)(x +6)

__

2) -15 = -1·15 = -3·5 = -5·3 . . . . . (-5)+(3) = -2, so these are the constants of interest

  x^2 -2x -15 = (x -5)(x +3)

__

3) 12 = -1·-12 = -2·-6 = -3·-4 . . . . . (-3) +(-4) = -7, so these are the constants of interest

  x^2 -7x +12 = (x -3)(x -4)

5 0
3 years ago
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