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arsen [322]
3 years ago
14

The radius of circle A is half of the radius of circle B. What is the area of circle A

Mathematics
1 answer:
labwork [276]3 years ago
8 0
The answer is D Explanation: I learned this already and I had this question before and I got it right
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Algebra 2 question need help thanks.​
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Describe what solving a trigonometric equation is.
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3 years ago
Hey how do you get from standard form to vertex form?
vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

  1. send the constant term to other side of equal                 \mathbf{ax^{2}+bx=-c}
  2. divide the whole equation be coefficient of \mathbf{x^{2}}, this will give     \mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}
  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
  5. rearrange the terms will give the vertex form of standard quadratic equation                                                                 \mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}

Follow the above procedure will give the vertex form.

(NOTE : you must know that \mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}. Use this equation in transforming the equation from step 3 to step 4)

8 0
3 years ago
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