Question

Can you answer this for me

Answer 1

We know

$\\ \sf{:}\Rrightarrow sin\Theta=\dfrac{Perpendicular}{Hypotenuse}$

Now

$\\ \sf{:}\Rrightarrow sinA=\dfrac{BC}{AC}$

$\\ \sf{:}\Rrightarrow sinA=\dfrac{11}{16}$

Answer 2

Answer: $\frac{11}{16}$

Step-by-step explanation:

11 is the opposite and 16 is the hypotenuse

So, the Sine of ∠A is 11/16

Hope this helps!! :)