The option that identifies the molar solubility of CdF₂ in pure water is;
A: The molar solubility of CdF₂ in pure water is 0.0585M, and adding NaF decreases this solubility because the equilibrium shifts to favor the precipitation of some CdF₂.
<h3>Understanding Molar Solubility</h3>
The equation of this reaction is;
CdF₂ (s) ⇄ Cd²⁺ (aq) + 2F⁻ (aq)
We are told that;
[Cd²⁺] (eq) = 0.0585m and [F⁻] eq = 0.117m.
Also, we see that 0.90m NaF is added to the saturated solution.
Now, molar solubility is defined as the number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated.
Thus, we can conclude that The molar solubility of CdF₂ in pure water is 0.0585M, and adding NaF decreases this solubility because the equilibrium shifts to favor the precipitation of some CdF₂.
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Answer:
34 because the shape is split.
Explanation:
Using sum and difference identities from trigonometric identities shows that; Asin(ωt)cos(φ) +Acos(ωt)sin(φ) = Asin(ωt + φ)
<h3>How to prove Trigonometric Identities?</h3>
We know from sum and difference identities that;
sin (α + β) = sin(α)cos(β) + cos(α)sin(β)
sin (α - β) = sin(α)cos(β) - cos(α)sin(β)
c₂ = Acos(φ)
c₁ = Asin(φ)
The Pythagorean identity can be invoked to simplify the sum of squares:
c₁² + c₂² =
(Asin(φ))² + (Acos(φ))²
= A²(sin(φ)² +cos(φ)²)
= A² * 1
= A²
Using common factor as shown in the trigonometric identity above for Asin(ωt)cos(φ) +Acos(ωt)sin(φ) gives us; Asin(ωt + φ)
Complete Question is;
y(t) = distance of weight from equilibrium position
ω = Angular Frequency (measured in radians per second)
A = Amplitude
φ = Phase shift
c₂ = Acos(φ)
c₁ = Asin(φ)
Use the information above and the trigonometric identities to prove that
Asin(ωt + φ) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)
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The functions f(x) and g(x) are represented by their equations
The correct statement is that function g(x) is translated 2 units down to function f(x)
<h3>How to determine the correct statement</h3>
The functions are given as:
f(x) = 3x - 2
g(x) = 3x
Substitute 3x for g(x) in function f(x)
f(x) = g(x) - 2
The above means that:
Function g(x) is translated 2 units down to function f(x)
Read more about translation at:
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