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stiks02 [169]
3 years ago
6

I need help like right now I have no idea what I’m looking at

Mathematics
1 answer:
weqwewe [10]3 years ago
4 0

Answer:

what grade are u in and what are the answer choices if the steps are the choices then try step 3

Step-by-step explanation:

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Michelle and Michael checked some books out of the library. 20% of the books Michelle checked out were fiction books, and 40% of
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Perctange is based on the total number. in this case you don't know it so you cant make such a guess.
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What’s the y intercept of y=-2x+6
Eva8 [605]
The y intercept is b in the formula y=mx+b
Y-int = 6
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3 years ago
Read 2 more answers
Which ordered pair is the solution to the system of equations?
prisoha [69]

Answer:

(3, -3)

Step-by-step explanation:

{у = 3х - 12

{4х + 6у = −6

4x + 6[3x - 12] = −6

4x + 18x - 72 = −6

−6 = −72 + 22x

+72 + 72

___________

66 = 22x

__ ___

22 22

3 = x [Plug this back into both equations above to get the y-coordinate of −3]; -3 = y

I am joyous to assist you anytime.

3 0
3 years ago
HELP!!!!!!!!!!!!!!! please show your work, look at the picture
Margarita [4]

Answer:

B= 2y(3)/7x(8)

C= 12/ x(3) y(3)

D= The same because nothing else can be done with it

(parnthaces) are exponents

6 0
3 years ago
Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
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