Find the area of the quadrilateral in the figure

If A = (4,-5) and B = (7.-9), what is the length of AB?

Nookie1986 [14]

Answer:

5

Step-by-step explanation:

We can figure out the length of AB by using the distance formula.

$D = \sqrt{(7-4)^{2} + (-9-(-5))^{2} }\\ D = \sqrt{(3)^{2} + (-4)^{2} }\\D = \sqrt{9 + 16}\\D = \sqrt{25}\\D=5$

So the distance is 5

5 0

3 years ago

Use the function below to find f(1). f9t0=4

ExtremeBDS [4]

The value of the F(1) is 1/2 option (C) is correct after plugging the value of t = 1 in the provided function.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is attached in the picture please refer to the picture.

We have a function:

$\rm F(t) = 4\dfrac{1}{2^{3t}}$

Plug t = 1

$\rm F(1) = 4\dfrac{1}{2^{3\times1}}$

After solving:

F(1) = 1/2

Thus, the value of the F(1) is 1/2 option (C) is correct after plugging the value of t = 1 in the provided function.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

6 0

2 years ago

Those are the math questions I need the answers of

Elena L [17]

Answer:

1)

$12\sqrt{18}-3\sqrt{50}+\sqrt{32}$

$12\sqrt{9}\sqrt{2}-3\sqrt{25} \sqrt{2} +\sqrt{16} \sqrt{2}$

$12\times3\sqrt{2} -3\times5\sqrt{2}+4\sqrt{2}$

$36\sqrt{2}-15\sqrt{2}+4\sqrt{2}$

$25\sqrt{2}$

2)

$\frac{1}{5+2\sqrt{6}}$

Multiply $5-2\sqrt{6}$ :

$\frac{1\times \left(5-2\sqrt{6}\right)}{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}$

Apply Difference of Squares formula: $(a+b)(a-b)=a^2-b^2$

$\frac{5-2\sqrt{6}}{5^2-\left(2\sqrt{6}\right)^2}$

$\frac{5-2\sqrt{6}}{25-2^2\left(\sqrt{6}\right)^2}$

$\frac{5-2\sqrt{6}}{25-4\times6}$

$\frac{5-2\sqrt{6}}{1}$

${5-2\sqrt{6}}$

a = 5, b = -2

7 0

4 years ago

How do you solve this??? I need it fast please help with steps.<br> (x+3)(x+1)^2(x−4)>0

scZoUnD [109]

Answer:

x < -3 or x > 4

Step-by-step explanation:

The product of the factors is 4th-degree, and the leading coefficient is 1 (positive).

The factors tell you the following about the zeros:

x = -3 . . . sign change from + to -

x = -1 . . . graph touches, but no sign change. - on either side of x=-1

x = 4 . . . sign change from - to +

__

The function will be positive for x < -3 and for x > +4.

_____

<em>Additional comments</em>

The value of the function is zero when any of its factors is zero. The value of a factor changes sign when the value of x changes from one side of the 0 to the other. For example, here, we have x+1 as a factor, so x=-1 is a zero. When x = -0.9, the factor is positive (-0.9 +1 = 0.1). When x = -1.1, the factor is negative (-1.1 +1 = -0.1). If this factor were to the first power, it would cause the value of the function to change sign at x=-1.

However, the factor (x+1) has an even power: (x+1)^2. That means when the factor is negative, its square is positive, and when the factor is positive, its square is positive. In short, the factor (x+1)^2 causes the function to be zero at x=-1, but does not make the function change sign there.

The product of all of these factors will result in a polynomial with x^4 as the highest-degree term. That means the function is of even degree. The leading coefficient is 1, so is positive, and the function will generally have a U-shape. The left-most (odd-degree) zero will be where the function changes sign from positive to negative. The right-most (odd-degree) zero will be where the function changes sign from negative to positive. Those zeros are x=-3 and x=+4, respectively. There are no places between these where the function changes sign, so these zeros are the ends of the regions where the function is positive (>0).

3 0

2 years ago

Please answer this (photo below)

lozanna [386]

Answer:

Please see attached image for the graph

Step-by-step explanation:

To graph the elevation versus time, we start by plotting the first point at time zero (when the climb begins) when Zane is 20 meters below the edge (-20 meters). This corresponds to the point (0, -20).

One second later (1 in the horizontal axis), Zane has moved up 4 meters, now reaching -16 meters. This is the point (1, -16) on the graph.

One second later at time 2 seconds, he is another 4 meters up which corresponds to the point (2, -12) on the graph.

you can go on like this plotting more points on the graph.

Please see the attached image that illustrates this and shows the appropriate line that represents Zane's position versus time (pictured in red)

7 0

3 years ago