If 12g of a radioactive substance are present initially and 8yr later only 6g remain, how much if the substance will be present
1 answer:
The weight of substance remaining after 13 years is 2.25 g.
Given:
Present weight of substance = 12 g
After 8 years weight remains = 6 gm
Now, weight loss in 8 year will be,
12-6=6 gm
So, weight loss in 1 year will be,
Total weight loss in 13 year will be,
The weight of substance remaining after 13 years will be,
Therefore, the weight of substance remaining after 13 years is 2.25 g.
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The missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.
<h3>What is a complex number?</h3>It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have the roots of a quadratic equation:
5 ± 3i
To find the quadratic equation:
(x - (5+3i))(x - (5-3i))
= x² -10x + 34
The missing value is 10x
The quadratic equation is:
= x² -10x + 34
Thus, the missing term in the provided quadratic equation is 10x if the roots of a quadratic equation are 5 ± 3i.
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