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nikdorinn [45]
3 years ago
9

If 12g of a radioactive substance are present initially and 8yr later only 6g remain, how much if the substance will be present

after 13 years?
Mathematics
1 answer:
Brums [2.3K]3 years ago
5 0

The weight of substance remaining after 13 years is 2.25 g.

Given:

Present weight of substance = 12 g

After 8 years weight remains = 6 gm

Now, weight loss in 8 year will be,

12-6=6 gm

So, weight loss in 1 year will be,

\dfrac{6}{8} =\dfrac{3}{4}

Total weight loss in 13 year will be,

\dfrac{3}{4}\times13=9.75

The weight of substance remaining after 13 years will be,

12- 9.75 = 2.25 \;\rm g

Therefore, the weight of substance remaining after 13 years is 2.25 g.

To know more about radioactive decay, refer to the link:

brainly.com/question/12116123

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A person has a bag containing quarters and dimes. There are a total of 72 coins in the bag, and the total value of the coins is
ipn [44]

Answer:

  • 40 quarters and 32 dimes

Step-by-step explanation:

<u>Given:</u>

  • Quarter = 25 ¢, number of quarters = q
  • Dime = 10 ¢, number of dimes = d
  • Total amount = $13.20 = 1320 ¢

<u>Required equations:</u>

  • q + d = 72
  • 25q + 10d = 1320

<u>Solve by elimination, multiply the first equation by 10 and subtract from the second equation:</u>

  • 25q + 10d - 10q - 10d = 1320 - 10*72
  • 15q = 600
  • q = 600/15
  • q = 40

<u>Find p:</u>

  • 40 + p = 72
  • p = 72 - 40
  • p = 32
6 0
2 years ago
4(b+1) ≤ 2(2b+1)+1<br> Is this equation no solution?<br> Very important
Dvinal [7]

Answer:

it does not have a solution

Step-by-step explanation:

4(b + 1) ≤ 2(2b + 1)+1

4b + 4 ≤ 4b + 2 + 1

0 ≤ -1

0 isn't less than or equal to -1

3 0
3 years ago
Read 2 more answers
Find the surface area of a hemisphere that has a volume of 486π <img src="https://tex.z-dn.net/?f=cm%5E%7B3%7D" id="TexFormula1"
Xelga [282]

\textit{volume of a hemisphere}\\ V=\cfrac{4\pi r^3}{3}\cdot \cfrac{1}{2}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=486\pi \end{cases}\implies 486\pi =\cfrac{4\pi r^3}{6} \implies 6(486\pi )=4\pi r^3 \\\\\\ \cfrac{6(486\pi )}{4\pi }=r^3\implies 729=r^3\implies \sqrt[3]{729}=r\implies \boxed{9=r} \\\\[-0.35em] ~\dotfill

\textit{surface area of a hemisphere}\\\\ SA=4\pi r^2\cdot \cfrac{1}{2}\implies \stackrel{\textit{we know that r = 9}}{SA=2\pi (9)^2}\implies SA=162\pi \implies SA\approx 508.94

6 0
2 years ago
Shall we made cupcakes and now she wants to frost them she has 4 cups of frosting it takes 1/3 of a cup of frosting for each cup
stira [4]
4 = 1/3x

she can frost 12 cupcakes
4 0
3 years ago
Read 2 more answers
what's the surface area of this square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall
Vadim26 [7]

The surface area of the square prism is 115 square inches

<h3>surface area of a pyramid</h3>

The surface area of a pyramid is equivalent to the sum of the faces of the pyramid

For the given square pyramid;

TSA = (5*5) + 4(1/2 * 9 * 5)

Simplify to have;

Surface area =25 + 4(45/2)

Surface area = 25 + 180/2

Surface area = 25. + 90

Surface area = 115 square inches

Hence the surface area of the square prism is 115 square inches

Learn more on surface area here: brainly.com/question/20771646

#SPJ1

7 0
1 year ago
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