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Sidana [21]
3 years ago
9

Find the value of x.

Mathematics
2 answers:
jek_recluse [69]3 years ago
5 0

Answer:

41 degrees

Step-by-step explanation:

180-90-49 = 41

IrinaK [193]3 years ago
3 0

Answer:

the answer is 49

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What is the area of the regular hexagon?
myrzilka [38]

Answer:

216 \sqrt{3} \: {in}^{2}

Step-by-step explanation:

Area \: of \: regular \: hexagon \\  =  \frac{ 3 \sqrt{3} }{2}  {side}^{2}  \\ =  \frac{ 3 \sqrt{3} }{2}  \times  {12}^{2}  \\ =  \frac{ 3 \sqrt{3} }{2}  \times  144 \\ =  { 3 \sqrt{3} } \times  72 \\  = 216 \sqrt{3}  \:  {in}^{2}  \\

3 0
3 years ago
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28 lb. 6 oz. − 11 lb. 5 oz. =
S_A_V [24]
17.0625 thats the answer
7 0
4 years ago
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An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0
4 years ago
You randomly choose one of the tiles shown. Select the favorable outcome(s) of choosing a 6.<br>​
Alona [7]

Answer:

If there are 6 tiles, the probability is 1/6

Step-by-step explanation:

6 0
4 years ago
Calculus Ch. 1.2 Classwork Problems Evaluating limits Graphically
nirvana33 [79]

Answer:

8) 1

9) -4

10)  -3

11)  -1

12)  1

13)  doesn't exist

14)  1

15)  doesn't exist

Step-by-step explanation:

8) when we approach x=-8 from left and from right, the function tends towards the value 1

9) when we approach x = -7, from the left the function gets towards 0, while when we approach it from the right it gets closer to -4

10) f(-3) = -3

11) When x approaches the value 4 from the left and from the right, f(x) gets closer to -1

12) f(4) is defined as 1

13) f(6) doesn't exist

14)  When x approaches 6 from the left and from the right, the function approaches 1

15)  When x approaches the value 7 from the left the function gets closer to 2, while when we approach x = 7 from the right the function gets toward 7. Because of this discrepancy, the limit doesn't exist.

3 0
4 years ago
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