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Artyom0805 [142]
2 years ago
6

Help please i’m giving away 15 points math grade 7

Mathematics
2 answers:
Gemiola [76]2 years ago
7 0

Answer:

3.6

Step-by-step explanation:

\frac{2}{3}(6a+9)=20.4

4a+6=20.4

4a=14.4

a=3.6

marusya05 [52]2 years ago
6 0
Simplify ———
5
Equation at the end of step
1
:

2 102
(— • (6a + 9)) - ——— = 0
3 5
STEP
2
:

2
Simplify —
3
Equation at the end of step
2
:

2 102
(— • (6a + 9)) - ——— = 0
3 5
STEP
3
:

STEP
4
:
Pulling out like terms

4.1 Pull out like factors :

6a + 9 = 3 • (2a + 3)

Equation at the end of step
4
:

102
2 • (2a + 3) - ——— = 0
5
STEP
5
:
Rewriting the whole as an Equivalent Fraction

5.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using 5 as the denominator :

2 • (2a + 3) 2 • (2a + 3) • 5
2 • (2a + 3) = ———————————— = ————————————————
1 5
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

5.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2 • (2a+3) • 5 - (102) 20a - 72
—————————————————————— = ————————
5 5
STEP
6
:

Pulling out like terms :

6.1 Pull out like factors :

20a - 72 = 4 • (5a - 18)

Equation at the end of step
6
:

4 • (5a - 18)
————————————— = 0
5
STEP
7
:

When a fraction equals zero :

7.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

4•(5a-18)
————————— • 5 = 0 • 5
5
Now, on the left hand side, the 5 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
4 • (5a-18) = 0

Equations which are never true:

7.2 Solve : 4 = 0

This equation has no solution.
A a non-zero constant never equals zero.

Solving a Single Variable Equation:

7.3 Solve : 5a-18 = 0

Add 18 to both sides of the equation :
5a = 18
Divide both sides of the equation by 5:
a = 18/5 = 3.600

One solution was found :
a = 18/5 = 3.600

Mark me as brainliest plsssss
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A constant force F = -31+43 - 2k is applied to an object that is moving along a straight line from the point (4,1,-5) to the poi
patriot [66]

I don't know if you meant

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or

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I'll assume the first force is correct.

The object in question undergoes a total displacement of

\vec d = (-4\,\vec\imath + 4\,\vec\jmath+4\,\vec k)\,\mathrm m - (4\,\vec\imath + \vec\jmath - 5\,\vec k)\,\mathrm m = (-8\,\vec\imath + 3\,\vec\jmath + 9\,\vec k)\,\mathrm m

Then the work <em>W</em> done by \vec F along this displacement is

W = \vec F \cdot \vec d = ((-3)\times(-8)+4\times3+(-2)\times9)=18\,\mathrm{Nm} = \boxed{18\,\mathrm J}

Another approach using calculus (it's overkill since \vec F is constant, but it doesn't hurt to check our answer): parameterize the line segment by

\vec r(t) = (1 - t)(4\,\vec\imath+\vec\jmath-5\,\vec k)\,\mathrm m + t(-4\,\vec\imath+4\,\vec\jmath + 4\,\vec k)\,\mathrm m \\\\ \vec r(t) = \left((4-8t)\,\vec\imath+(1+3t)\,\vec\jmath+(-5+9t)\,\vec k\right)\,\mathrm m

with 0 ≤ <em>t</em> ≤ 1.

Then the work <em>W</em> done by \vec F along the given path is equal to the line integral,

\displaystyle W = \int_0^1 \vec F(\vec r(t)) \cdot \frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt \\\\ W = \int_0^1 \left((-3\,\vec\imath+4\,\vec\jmath-2\,\vec k)\,\mathrm N\right) \cdot \left((-8\,\vec\imath+3\,\vec\jmath+9\,\vec k)\,\mathrm m\right) \,\mathrm dt \\\\ W = \int_0^1((-3)\times(-8)+4\times3+(-2)\times9)\,\mathrm{Nm}\,\mathrm dt \\\\ W = 18\,\mathrm{Nm} \int_0^1\mathrm dt \\\\ W = 18\,\mathrm{Nm} = \boxed{18\,\mathrm J}

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3 years ago
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Troyanec [42]

Answer:

In mathematics and statistics, the arithmetic mean, or simply the mean or average when the context is clear, is the sum of a collection of numbers divided by the number of numbers in the collection. The collection is often a set of results of an experiment, or a set of results from a survey.

Step-by-step explanation:

8 0
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cupoosta [38]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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