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Alborosie
3 years ago
13

Round 2,641 to the nearest thousand. Round 2,641 to the nearest thousand?

Mathematics
2 answers:
Elenna [48]3 years ago
8 0

Answer:

2641

we round off 2

then we get,

2641=3000

mash [69]3 years ago
3 0
The answer is 3,000 as I have answered on your other question. :)
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Will give brainliest!!
swat32

Answer:

its 5 hours i think

Step-by-step explanation:

3 0
3 years ago
Charlotte reads 8 1/3 pages of a book in 10 minutes. What is her average reading rate in pages per minute?
sukhopar [10]
8\frac{1}{3} = \frac{25}{3}

25/3 pages of a book in 10 minutes

Multiply both numbers by the reciprocal of 10, which is 1/10

\frac{25}{3} \times\frac{1}{10} = \frac{25}{30}=\frac{5}{6}

10\times\frac{1}{10}= 1

So, Charlotte reads 5/6 pages of a book in 1 minute.
8 0
3 years ago
Graph - 9x + 6y = 18 using linear standard form
postnew [5]

Answer:

The graph is attached Below and the plotting is given below.

Step-by-step explanation:

Given:

-9x + 6y = 18

Solution:

To draw a line on a graph the required minimum two points but here we will have three points as point A, point B, and point C.

For point A

Put x = -4 in the given equation we get

-9×-4 + 6y = 18

6y = 18-36

∴ y=\frac{-18}{3}\\ \\y=-3

∴ Point A ≡ ( -4, -3 ).

For point B

Put x = -2 in the given equation we get

-9×-2 + 6y = 18

6y = 18 - 18

6y = 0

∴ y=\frac{0}{3}\\ \\y=0

∴ Point B ≡ ( -2, 0 ).

For point C

Put x = 0 in the given equation we get

-9×0 + 6y = 18

6y = 18

∴ y=\frac{18}{3}\\ \\y=3

∴ Point C ≡ ( 0, 3 ).

Now we have Point A ,B and C join it and you will have Line.

3 0
3 years ago
Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
2 years ago
If a study determines the difference in average salary for subpopulations of mechanical engineers and civil engineers is NOT sig
uysha [10]

Both are not earning different salaries.

If a study determines the difference in average salary for subpopulations of mechanical engineers and civil engineers is NOT significant, then the subpopulations of mechanical and civil engineers are not earning different salaries.
Study determines that there is not any significant study so thats why both are not earning.


Learn more about average median on:

brainly.com/question/14532771

#SPJ10

3 0
1 year ago
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