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dmitriy555 [2]
3 years ago
7

What is the sign of the product (8)(-23)(-21)(-29) ?

Mathematics
2 answers:
max2010maxim [7]3 years ago
6 0
It's Negative -112,056 u multiply left to right and end up with a negative
Jlenok [28]3 years ago
5 0
Hey there!

When you multiply across, you get the following product:
<span>
8 </span>× –<span>23 </span>× –<span>21 </span>× –<span>29
</span>–184 × –21 × –29
3864 × –29
–112,056

The sign will be negative. 

Hope this helped you out! :-)<span />
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Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
2 years ago
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Step-by-step explanation:

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2 years ago
What is the area of the parallelogram?
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Answer: D

Step-by-step explanation:

5x6=30

3 0
3 years ago
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Answer:

10 weeks

Step-by-step explanation:

205+2t=195+3t

      -2t         -2t

205=195+t

-195 -195

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3 0
3 years ago
Determine the height
tangare [24]

Answer:

The height of the model is 138 cm.

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Simply multiply the height by the scale factor.

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1.38*100 = 138

The height of the model is 138 cm.

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2 years ago
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