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3 years ago

Find the area of the shape below. 16 cm 7 cm 7 cm 20 cm

Mathematics

2 answers:

Nataly [62]3 years ago

6 0

Answer:

230cm^2

Step-by-step explanation:

20x9=180

180/2=90

20x7=140

140+90=230cm^2

Ira Lisetskai [31]3 years ago

4 0

Step-by-step explanation:

ar of quadilateral

=16×7×7×20

=12080cmsq

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a container of candy is shaped like a cylinder and has a volume of 125.6 cubic centimeters. If the heights of the container is 1

Elenna [48]

The radius of the container is 2 centimeter

<h3><u>Solution:</u></h3>

Given that a container of candy is shaped like a cylinder

Given that volume = 125.6 cubic centimeters

Height of conatiner = 10 centimeter

To find: radius of the container

We can use volume of cylinder formula and obatin the radius value

<em><u>The volume of cylinder is given as:</u></em>

$\text {volume of cylinder }=\pi r^{2} h$

Where "r" is the radius of cylinder

"h" is the height of cylinder and $\pi$ is constant has value 3.14

Substituting the values in formula, we get

$\begin{array}{l}{125.6=3.14 \times r^{2} \times 10} \\\\ {r^{2}=\frac{125.6}{31.4}} \\\\ {r^{2}=4}\end{array}$

Taking square root on both sides,

$r = \sqrt{4}\\\\r = 2$

Thus the radius of the container is 2 centimeter

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2 years ago

Find the surface area of this cube. Be sure to include the correct unit in your answer.

Alexxx [7]

Answer:

486 cm

Step-by-step explanation:

9×9=81

there are 6 faces

81×6=486

7 0

1 year ago

at the football game on friday andrew threw 15 passes. he completed 10 for 120 yards what was his average per completion

Sunny_sXe [5.5K]

Answer:

120 divided by 10 is 12 yards per completion

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2 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

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2 years ago

I need help with this problem

yKpoI14uk [10]

-24 + y= -120

y= -96 is the answer to the problem

6 0

2 years ago

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