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2 years ago

Write an expression that is equivalent to (-16)^-2

Mathematics

1 answer:

raketka [301]2 years ago

8 0

Answer:

1/256

Step-by-step explanation:

(-16)^-2

= 1/(-16)^2

= 1/ (-16· -16)

= 1/ 256

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Instructions: Solve the following literal equation. Solve 4x – 2y = 18 for y. y =

krok68 [10]

Answer:

$y = - 9 + 2x$

Step-by-step explanation:

Objective: Use the rules of Algebra to isolate y.

$4x - 2y = 18$

$- 2y = 18 - 4x$

$y = \frac{18 - 4x}{ - 2}$

$y = - 9 + 2x$

4 0

3 years ago

The average smoker typically pays 15% higher life insurance costs than the average non-smoker. If the monthly cost to a non-smok

Maksim231197 [3]

Answer:

$75

Step-by-step explanation:

The average smoker pay 15% life insurance than the non-smoker

The monthly cost of a non-smoker is $500 per month

Therefore the amount that would be paid by the average smoker in a month can be calculated as follows

= 500 × 15/100

= 500 × 0.15

= 75

Hence the amount to be paid is $75

5 0

3 years ago

Can u help me please better picture

gladu [14]

Hi, there.

For this question, we can apply the Pythagorean theorem $a^2 + b^2 = c^2$ .

I'm sure you've seen this equation before, and they kind of tried to trip you up with this problem. Trust me, it's easier than it looks. Let's break it down.

Lengths a and b both have the value of 48, which means that the value s in $\sqrt{2s^2}$ is 48, because the length of the hypotenuse is the same as the length and height squared multiplied by 2.

Plug in the value for c: $a^2 + b^2 = (\sqrt{2s^2})^2$

Plug in the value for s:

$(\sqrt{2(48^2)})^2$

Do the innermost exponents first:

$(\sqrt{2(2304)})^2$

The square root symbol and the power of 2 cancel each other out, so we are left with:

s = $2(2304)$ , so the hypotenuse is 4608 inches.

4 0

3 years ago

Find cos θ if sin θ = -12/13 and tan θ > 0

Anarel [89]

SinФ=-12/13
cosФ=Base/hypotenus
(hy)^2-(perpendicular)^2=(base)^2=13^2-12^2=5
cosФ=-5/13

6 0

3 years ago

A trapezium of area 105 cm2 has parallel sides of length 5cm and 9 cm how far apart are the parallel sides

Tanzania [10]

For a trapezoid:
the area equals the product of half the sum of the two bases' length and the normal height between them

so that, we can write:
$105= \frac{5+9}{2}*h\\~\\h=15~~cm$

Hence the parallel sides are 15 cm apart.

I hope that helps!

6 0

4 years ago