Pythagorean thoerem
we imagine the wall as a leg of a right triangle, the ladder is the hypotonuse and the distance from the bottom of the ladder to the wall is the other leg
so if we have a right triangle with leg length a and b and hypotnuse length c then
a²+b²=c²
so
given that one of the legs is 9ft (9 ft is the height of the triangle)
and the hypotnuse is 12 ft (length of ladder)
then say the last leg is x
so
x²+9²=12²
x²+81=144
mius 81 both sides
x²=63
sqrt both sides
x=√63
x=3√7
you should place it 3√7ft or about 7.9 or 8ft away
3. x: 180-99 = 81º (angles on a straight line equals 180)
y: 115-81 = 34º (exterior angle is sum of opposite interior angles)
4. y: 180-64 = 116 (angles on a straight line equals 180)
x: 126º
two steps
angles on straight line equals 180: 180-118 = 62º
exterior angle is sum of opposite interior angles: 62+64 = 126º
sorry if i misread any of the numbers, let me know if i did and i'll fix it
Answer:
100 ÷ 59 100. 59. divide those
Step-by-step explanation:
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