When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
289/290
Step-by-step explanation:
Given that the chance of Donnell being selected is 1/290
then P( Donnell being selected )= 1/290
Since Donnell and Maria are both member of a population.
from probability theorem which gives the likely hood of an event to happen which cannot be more than 1, then the probability of Donnell and Maria to be selected is 1
P(Donnell and Maria)= 1
But the chance of Donnell being selected is 1/290
Then,
1/290 + P(Maria)= 1
P(Maria)= 1-(1/290)
= 289/290
the chance of Maria being selected is 289/290
