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Crank
3 years ago
6

63. An art teacher gave each group of students packages of clay. If there were 6 students in each group, how many packages of cl

ay would the teacher have used for a class of 30 students?​
Mathematics
2 answers:
alexandr402 [8]3 years ago
7 0

Answer:

5

Step-by-step explanation:

you divide 6/30=5

hope this helps

finlep [7]3 years ago
7 0
572829928373737737372727728282929484747747383737737373773736:)
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How do you solve 12-3m=18
OLEGan [10]
Subtract 12 on both sides and both 12s cross out leaving -3m= 6 and then divide -3 on both sides and your answer should be m=-2
3 0
3 years ago
Simplify:9-1÷2÷27^2÷3​
sammy [17]

<u>First let's calculate the exponents.</u>

27^2 : 729 = 9-1\div \:2\div \:729\div \:3

<u>Now we should multiply and divide.</u>

<u />1\div2\div729\div3:\frac{1}{4374} = 9-\frac{1}{4374}<u />

<u>Now we should add and subtract.</u>

<u />9-\frac{1}{4374} :\frac{39365}{4374} =  \frac{39365}{4374}<u />

<u>Convert the improper fractions into mixed numbers.</u>

<u />8\frac{4373}{4374}<u />

<u />

<u>Answer : </u>

<u />8\frac{4373}{4374}<u />

<u />

5 0
3 years ago
(4y − 3)(2y2 + 3y − 5)
VladimirAG [237]

Answer:

8y^3+6y^2-29y+15

Step-by-step explanation:

the correct expression is

(4y − 3)(2y^2 + 3y − 5)

Given data

We have the expression

(4y − 3)(2y^2 + 3y − 5)

let us open bracket

8y^3+12y^2-20y-6y^2-9y+15

Collect like terms

8y^3+12y^2-6y^2-20y-9y+15

8y^3+6y^2-29y+15

4 0
3 years ago
Why is it impossible to determine whether the equation 5x+10=25 is true / false ? Explain
Assoli18 [71]

You need to know the value of X to determine whether or not the equation is true.

8 0
4 years ago
Read 2 more answers
A multiple-choice test in which each question has 4 choices only one of which is correct. Assume that 9 questions are answered b
yaroslaw [1]

Answer:

Therefore, the probability is P=0.0084.

Step-by-step explanation:

We know that  a multiple-choice test in which each question has 4 choices only one of which is correct. Assume that 9 questions are answered by guessing randomly.

Because we have 4 choices only one of which is correct, we get that p=0.25 and q=0.75.

We calculate  the probability of getting exactly 6 correct answers.

n=9 and k=6.

P=C_k^n\cdot p^k\cdot q^{n-k}\\\\P=C_6^9\cdot 0.25^6\cdot 0.75^3\\\\P=84\cdot 0.0001\\\\P=0.0084

Therefore, the probability is P=0.0084.

7 0
3 years ago
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