Actually Welcome to the Concept of the circles.
It's is universally proven that ratio of circumference and diameter is always π
hence the decimal value is π = 3.14
===> answer is option B.) 3.14
Scale factor is a ratio. The correct option is C.
<h3>How are
scale drawings formed?</h3>
For a particular scale drawing, it is already specified that all the measurements' some constant scaled version will be taken. For example, let the scale be K feet to s inches.
Then it means
All feet measurements will then be multiplied by s/k to get the drawing's corresponding lengths.
The length of AB can be written as,
AB = √[(1-4)²+ (1-1)²]
AB = 3
Since the length A'B' is 6 units, therefore, the scale factor will be,
Scale factor = (Length after transformation)/(Length before transformation)
Scale factor = 6 /3 = 2
Hence, the correct option is C.
Learn more about Scale factors:
brainly.com/question/8765466
#SPJ1
The answer should be 6! all you have to do is plug the numbers into the equation!
it would be like this:
-1^2+3^2+(-1)-3
doing all of that would equal 6!
Answer:
D. 9/DF=18/16.......the answer
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
#SPJ1
