Question

What is the equation of the line that passes through the point (-1, -7) and has a slope of 2?

Answer 1

Answer:

y=2x-5

Step-by-step explanation:

The slope-intercept form of an equation looks like y=mx+b. Where m is the slope and b is the y-intercept. The slope is already given to us, so m is 2.

To find b use the equation $b=y_1-m*x_1$. So, to find the y-intercept use b=-7-(2*-1). This equals b=-5.

So, plug in the values to get the final equation y=2x-5.

Answer 2

Answer:

y = 2x - 5

Explanation:

Since the slope is given as 2, we can substitute this into the equation:

y = 2x+b

Now, we can manipulate the point (-1,-7) to be in the form of a y-intercept - (0, y).

Note that a slope of 2 = 2/1, which means the rise = 2(which is added to the y) and run = 1(which is added to the x).

Adding this to our point of (-1,-7), we get:

((-1+1),(-7+2)) = (0, -5)

Therefore -5 is our y-intercept.

Now, substituting -5 into our equation, we get:

y = 2x + -5