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svlad2 [7]
3 years ago
5

A total of $30,000 is invested in two corporate bonds that pay 5.5% and 6.25% simple interest. the investor wants an annual inte

rest income of %1800 from the investments. what is the most that can be invested in the 5,5% bond?
Mathematics
1 answer:
lubasha [3.4K]3 years ago
6 0

Answer:

  $10,000

Step-by-step explanation:

Let x represent the amount invested in the 5.5% bond.

For an annual income of $1800, we want ...

  (5.5%)x + (6.25%)(30,000-x) = 1800

  (-0.75%)x + 1875 = 1800

  -0.0075x = -75 . . . . . . . . . subtract 1875

  x = 10,000 . . . . . . . . . . . . . divide by -0.0075

At most $10,000 should be invested at 5.5% to obtain at least $1800 in interest.

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Answer:

The answer is 1

Step-by-step explanation:

Start by solving the division part of the equation. In order to do that, you have to flip the fraction (reciprocal) and switch from division to multiplication, thus getting 3 x 3 = 9. Now you have 9 – 9 + 1, and from there you can simply work from left to right and get your final answer: 1.

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After Two Hours.

Step-by-step explanation:

A simple way to do it is to:

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Step-by-step explanation:

The factors are the parts that are being multiplied together.

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Mara simplifies the expression: -(7x - 3y) + 2(x + 4). Her work is shown. In what step does she make a mistake?
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<em><u>Correct steps are shown</u></em>

<em><u>Correct simplified expression is:</u></em>

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<em><u>Solution:</u></em>

<em><u>Given that: Mara simplifies the expression</u></em>

-(7x - 3y) + 2(x+4)

<em><u>Correct steps are:</u></em>

From given,

-(7x - 3y) + 2(x+4)

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