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mr Goodwill [35]
2 years ago
15

Factorise x squared plus 10x

Mathematics
2 answers:
sattari [20]2 years ago
6 0

We know, factorisation is the process of writing a number or another mathematical object as a product of several factors, usually smaller or simpler objects of the same kind.

  • x² + 10x

Now we should take x common from both the terms.

  • = x (x + 10)

<u>Answer</u><u>:</u>

<u>x </u><u>(</u><u>x </u><u>+</u><u> </u><u>1</u><u>0</u><u>)</u>

Hope you could understand.

If you have any query, feel free to ask.

andrew-mc [135]2 years ago
3 0

Answer:

\bold{x(x+10)}

Step-by-step explanation:

Hi there!

Factoring is the opposite of distributing.

We know what distributing is:

a(b+c)=ab+ac

Well, this is factoring:

ab+ac=a(b+c)

So, let's factorise the given expression:

\bold{x^{2} +10x}

What's the common term? That's right, x.

So, we factor x out:

\bold{x(x+10)}

Hope it helps! Enjoy your day!

~Just a teen willing to help others

\bold{Besties4Ever:-):-):-)}

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Given:

There are two consecutive odd integers such that the square of the first added to 3 times the second, is 24.

To find:

Part a: Define the variables.

Part b: Set up an equations that can be solved to find the integers.

Part c: Find the integers.

Solution:

Part a:

Let x be the first odd integers. Then next consecutive odd integer is x+2, because the difference between two consecutive odd integers is 2.

Part b:

Square of first odd integers = x^2

Three times of second odd integers = 3(x+2)

It is given that the sum of square of first odd integers and three times of second odd integers is 24. So, the required equation is:

x^2+3(x+2)=24

Part c:

The equation is:

x^2+3(x+2)=24

It can be written as:

x^2+3x+6=24

x^2+3x+6-24=0

x^2+3x-18=0

Splitting the middle term, we get

x^2+6x-3x-18=0

x(x+6)-3(x+6)=0

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x=3,-6

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Second odd integer = x+2

                                  = 3+2

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Therefore, the two consecutive odd integers are 3 and 5.

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