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saveliy_v [14]
3 years ago
5

Finish the sequence 1,1,2,3,5,8,_,_,_

Mathematics
2 answers:
arlik [135]3 years ago
7 0
The Fibonacci sequence has to be thought of in these terms:

F₀, F₁, F₂, F₃, F₄, F₅, F₆, F₇, etc, etc

----------------------

Now:

F₀=0

F₁=1

The formula you use to get the other numbers is:

F_{n} = F_{n-1} + F_{n-2}

--------------

So:

F_{2} = F_{2-1} + F_{2-2} = F_{1} + F_{0} =1+0=1

And:

F_{3}= F_{3-1} + F_{3-2}  = F_{2} + F_{1} =1+1=2

------------

If you continue using the formula, you should get a sequence that starts off like this:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, etc, etc

Papessa [141]3 years ago
3 0
This is a Fibonacci sequence
1; 1
1 + 1 = 2
1 + 2 = 3
2 + 3 = 5
3 + 5 = 8
next terms:
5 + 8= 13
8 +13 = 21
13 + 21 = 34


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Answer:

Factors: (x²y+6)(y²-11)

<h2 />

Step-by-step explanation:

Here's the original equation.

x²y³ - 11x²y + 6y² - 66

Let's separate it into two groups to make it easier.

(x²y³ - 11x²y) + (6y² - 66)

Let's take a look at (x²y³ - 11x²y) first. Do we notice anything that can be removed from the parentheses?

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So  (x²y³ - 11x²y) becomes x²y (y²-11)

This works because if we multiply x²y * (y² - 11) we get (x²y³ - 11x²)

Let's apply this same idea to (6y² - 66).

6 is the only thing in common between the two polynomials.

If we follow the same steps we get 6 (y²-11).

Notice how when we simplified both groups they each had something on the outside and (y² - 11) in the parentheses?

So lets combine the things that were on the outside of both (y² - 11).

What was on the outside of each? x²y was on the outside for the first one, and 6 for the outside of the second one.

This means that if we combine everything and simplify, the factors we have are (x²y+6)(y²-11).

If you want to confirm, work your way backwards using the distributive property. You'll find that when you multiply (x²y+6) * (y² -11) you'll get = x²y³ - 11x²y + 6y² - 66. That was the original equation, so we know that these are the factors.

Hope that helps!

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prisoha [69]

Answer:

you can be on a call back at your the one in your the one in your office at it and

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