The tenth position is the one that goes after the decimal point.
To round a number, you have to take into account the following:
1. If the number that goes after the position we are going to round to is greater than 5, we round to the next number in that position.
2. If the number that goes after the position we are going to round to is less than 5, we round to the same number in that position.
In this case, the number that is on the tenth's position is 4. The number that is after this position is 1, which is less than 5, then we round the number in this positon to 4.
The rounded number would be:
0.85$ for 1 cups
1$ for 1/0.85 cups
55.25$ for [1/0.85]*55.25 = 55.25/0.85 = 65 cups
Don’t stress. try taking a nap. or watching a movie. Or listen to calming music.
Answer:
Step-by-step explanation:
a) ![\int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B%5Cinfty%7D%20_1%20%7B%5Cfrac%7B1%7D%7Bn%5E4%7D%20%7D%20%5C%2C%20dn%5C%5C%20%3D%5Cfrac%7Bn%5E%7B-3%7D%20%7D%7B-3%7D)
Substitute limits to get
= ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
Thus converges.
b) 10th partial sum =
![\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B10%7D%20_1%20%7B%5Cfrac%7B1%7D%7Bn%5E4%7D%20%7D%20%5C%2C%20dn%5C%5C%20%3D%5Cfrac%7Bn%5E%7B-3%7D%20%7D%7B-3%7D)
=![\frac{-1}{3} (0.001-1)\\= 0.333](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B3%7D%20%280.001-1%29%5C%5C%3D%200.333)
c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)
where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .
(question is not clear)
Answer: x < 11.9
Step-by-step explanation: