Answer:
I suggest PHOTO MATH app for that question download mo po:)
Answer: The length of segments between this point and the vertices of greater base are and 18.
Step-by-step explanation:
Let ABCD is the trapezoid, ( shown in below diagram)
In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7
Let P is the point where The extended legs meet,
So, according to the question, we have to find out : AP and BP
In Δ APB and Δ DPC,
∠ DPC ≅ ∠APB ( reflexive)
∠ PDC ≅ ∠ PAB ( By alternative interior angle theorem)
And, ∠ PCD ≅ ∠ PBA ( By alternative interior angle theorem)
Therefore, By AAA similarity postulate,
Let, DP =x
⇒
⇒ 33 +11x = 18x
⇒ x = 33/7=
Thus, PD=
But, AP= PD + DA
AP=
Now, let PC =y,
⇒
⇒ 77 + 11y = 18y
⇒ y = 77/7 = 11
Thus, PC= 11
But, PB= PC + CB
PB= 11+7 = 18
So they’re supplementary angles which means that they add up to 180°… The equation would be: 5w+1+7w-7=180
5w+1+7w-7=180 (combine like terms)
12w-6=180
+6 +6
12w=186
w=15.5
Im not sure what they’re asking for but if they’re asking for w, your answer is 15.5, if they’re asking for the angle measure on the left, your answer is 78.5° & if they’re asking for the angle measure on the right, your answer is 101.5° :) hope this helps
The solution to the problem is as follows:
<span>1∙5µm² = ? m²
1m * 1m = 1m²
But 1m = 1,000,000µm = 1x10^6µm
1x10^6µm * 1x10^6µm = 1m²
1x10^12µm² = 1m² (Now, divide both sides by 1x10^12).
1x10^12µm² /(1x10^12) = 1m² /(1x10^12)
1µm² = 0∙000 000 000 001 m² (x both sides by by 1∙5).
1∙5µm² = 0∙000 000 000 0015 m²
1∙5µm² = 1∙5x10^-12 m²
</span>I hope my answers has come to your help. God bless and have a nice day ahead!
Answer:
When you have large numbers to divide,
draw a tableau for long division on the side.
Write the steps that will be your guide,
D, M, S, B and R – Abide by to long divide!
Step-by-step explanation: