Answer:
Step-by-step explanation:
In an isosceles trapezoid, the opposite sides are equal.
The formula for determining the area of a trapezoid is expressed as
Area = 1/2(a + b)h
Where
a and b are the length of The bases are the 2 sides of the trapezoid which are parallel with one another.
h represents the height of the trapezoid.
From the information given,
a = 6
b = 8
height = 16
Therefore,
Area of trapezoid = 1/2(6 + 8)16
= 1/2 × 14 × 16 = 112 square units
If you have a calculator with statistical functions, that's the way to go.
On my TI-83, I typed in invNorm(0.88) and got the result z = 1.17.
88% of the area under the normal curve is to the left of z = 1.17.
(Bowls, Height) (1, 2) (5,5)
Slope is (5-2)/(5-1) = 3/4 inch
y = (3/4)x + b
(2) = (3/4)(1) + b
(2)-(3/4) = b
B=1.25. Y= 0.75*x + 1.25.
Part B
X is the number of bowls in the stack and Y is the corresponding height of the stack.
AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117
Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9

Therefore AB is 9 cms.
Answer:
There is no change.
Step-by-step explanation: