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WARRIOR [948]
2 years ago
6

20 POINTS!!

Mathematics
1 answer:
Sedaia [141]2 years ago
7 0

Answer:

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x=3/2

Decimal Form:

x=1.5

Mixed Number Form:

x =1 1/2

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Find the area of the Shaded region in square centimeters ​
exis [7]
The total area is the area of the rectangle minus the area of the triangle

Area of rectangle= 12x4=48

Area of triangle=0.5x9x4=18

Area of shaded region= 48-18
=30cm^2
8 0
3 years ago
What is 1.378 as a percent?
Finger [1]

Just like any other number . . .  If you want to change the number to
percent, either multiply it by 100, or move the decimal point 2places
to the right.

                 1.378   ==>   <em>137.8%</em>


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4 years ago
Find the area of the triangle below ( example A )
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I think it is 16.4 but I think
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3 years ago
Which function is equivalent to 9(x) = 9x2 – 24x + 16
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Step-by-step explanation:

3 0
3 years ago
What is the difference in speed between two cars when one traveled 175 km in 4 hours and the other traveled the same distance in
vovangra [49]
<h3>Given :</h3>
  • Distance = 175
  • Time 1 = 4 hours

\\  \\

<h3>To find:</h3>
  • Different between two speeds when distance is same.

\\  \\

<h3>Solution:</h3>

<u>Part</u><u> </u><u>1</u><u> </u><u>:</u>

In first part we will find speed 1 in which time is 4 hours

we know:-

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

So:-

\dashrightarrow\sf speed_1 =  \dfrac{distance}{time_1}

\\  \\

\dashrightarrow\sf speed_1 =  \dfrac{175}{4}

\\  \\

\dashrightarrow\bf speed_1 =  43.75 \: km {h}^{ - 1}

<u>Part 2</u>

In first part we will find speed 2 in which time is 3 hours

Again:

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{distance}{time_2}

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{175}{3}

\\  \\

\dashrightarrow\bf speed_2 = 58.33kmh^{-1}

\\  \\

<u>Part 3</u>

In this part we will find different between speed 1 and speed 2

\bigstar  \boxed{\rm Difference = speed_2 - speed_1}

\\  \\

So :

\dashrightarrow\sf Difference = speed_2 - speed_1 \\

\\  \\

\dashrightarrow\sf Difference =58.33 - 43.75\\

\\  \\

\dashrightarrow\bf Difference =14.58kmh^{-1}\\

\\  \\

\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}

4 0
3 years ago
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