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ollegr [7]
3 years ago
14

A rectangular garden has dimensions of 19 feet by 16 feet. A gravel path of equal width is to be built around the garden. How wi

de can the path be if there is enough gravel for 246 square feet?
OA 5ft
OB. 3 ft
OC. 41
OD. 5.5 ft
Mathematics
1 answer:
Virty [35]3 years ago
6 0

Answer:

A rectangular garden has dimensions of 19 feet by 16 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 246 square feet?

OA 5ft

OB. 3 ft

OC. 41

OD. 5.5 ft

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KiRa [710]

Answer:

y = \dfrac{1}{3}x + 1

Step-by-step explanation:

The given line is in slope-intercept form,

y = mx + b,

where m is the slope.

The slope of the given line is 1/3, so m = 1/3.

Parallel lines have equal slopes, so the slope of the parallel line is also 1/3.

y = 1/3 x + b

Now we can find the equation of the parallel line through point (6, 3) by using the given point's coordinates for x and y and solving for b.

3 = (1/3)(6) + b

3 = 2 + b

b = 1

Equation: y = \dfrac{1}{3}x + 1

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8+n^2

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Answer:

63

Step-by-step explanation:

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