Question

Please plot this linear equation on a graph, and also explain how to plot it. d="TexFormula1" title="y=3x-7" alt="y=3x-7" align="absmiddle" class="latex-formula">

Answer 1

Answer:

See below:

Step-by-step explanation:

Hello! I hope you are having a nice day.

We can solve this equation in a single step, we just need a bit of theory and a graph.

We can first see that its in $y=mx+b$ form. Which is also known as Slope-Intercept form.

This means that we know the following.

• $b$ is the y coordinate of the y intercept.
• $m$ is the slope of the line.

Since we know that, we can see that from our equation that the slope of the line is 3 and the y intercept is (0,-7).

Now that we've gotten that, we can start graphing.

The y intercept is -7 so we can plot (0,-7) as one of our points.

The slope of 3 means that we got up 3 units then right a single unit.

Therefore, another point could be (1,-4).

With our two points, we can create our graph by creating a straight line through those two points and therefore plotting our line.

Cheers!

Answer 2

Answer:

Step-by-step explanation:

y = 3x - 7 is a linear equation with y-intercept -7 (or    (0, -7)   ) and slope 3.  These two quantities are instantly readable from the equation.

There are several ways in which we may graph this equation.  One is to plot the y-intercept (0, -7)  Then choose an x-value, such as 3, and evaluate the function at that x value.  We see that y = 9 - 7, or y = 2, when x = 3. Then another point on the graph besides (0, -7) is (3, 2).  Plot (3, 2) and then draw a line through the two plotted points.

Here's another way:

The slope here is 3, or 3/1, which represents rise / run.  Plot (0, -7) as before.

Move your pencil from (0, -7) 1 space to the right and 7 spaces up.  Then plot a new point at that location.  Draw a line through (0, -7) and (1, 0).