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Lelu [443]
2 years ago
5

Please plot this linear equation on a graph, and also explain how to plot it.

d="TexFormula1" title="y=3x-7" alt="y=3x-7" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
olasank [31]2 years ago
6 0

Answer:

See below:

Step-by-step explanation:

Hello! I hope you are having a nice day.

We can solve this equation in a single step, we just need a bit of theory and a graph.

We can first see that its in y=mx+b form. Which is also known as Slope-Intercept form.

This means that we know the following.

  • b is the y coordinate of the y intercept.
  • m is the slope of the line.

Since we know that, we can see that from our equation that the slope of the line is 3 and the y intercept is (0,-7).

Now that we've gotten that, we can start graphing.

The y intercept is -7 so we can plot (0,-7) as one of our points.

The slope of 3 means that we got up 3 units then right a single unit.

Therefore, another point could be (1,-4).

With our two points, we can create our graph by creating a straight line through those two points and therefore plotting our line.

Cheers!

Svetach [21]2 years ago
4 0

Answer:

Step-by-step explanation:

y = 3x - 7 is a linear equation with y-intercept -7 (or    (0, -7)   ) and slope 3.  These two quantities are instantly readable from the equation.

There are several ways in which we may graph this equation.  One is to plot the y-intercept (0, -7)  Then choose an x-value, such as 3, and evaluate the function at that x value.  We see that y = 9 - 7, or y = 2, when x = 3. Then another point on the graph besides (0, -7) is (3, 2).  Plot (3, 2) and then draw a line through the two plotted points.

Here's another way:

The slope here is 3, or 3/1, which represents rise / run.  Plot (0, -7) as before.

Move your pencil from (0, -7) 1 space to the right and 7 spaces up.  Then plot a new point at that location.  Draw a line through (0, -7) and (1, 0).

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4 years ago
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Intercepts:
Tema [17]
An x-intercept is the point where the function passes the x axis at y=0.
The y-intercept is the point where the function crosses the y axis at x=0

1. It is an x-intercept, so y = 0. The ordered pair would be (-6, 0)
2. It is a y-intercept, so x = 0. The ordered pair would be (0, -2.3)
3. It is a y-intercept, so x=0. The ordered pair would be (0, 3/4)

To find the x-intercept, set y = 0. To find the y-intercept, set x=0

4. y-intercept: y = 3(0) -9. y = -9 The y-intercept is at (0, -9)
x-intercept: 0 = 3x -9. 9 = 3x. x = 3. The x-intercept is at (3, 0)

5. x intercept: 0 = 5x +10. -10 = 5x. x = -2. The x-intercept is at (-2, 0)
y-intercept: y = 5(0) + 10. y = 10. The y-intercept is at (0, 10)

If you look at finding the y-intercepts in the two problems above, you may see there is a pattern forming. The y-intercept is the number that your adding or subtracting that is located after the x (ex. y = 4x - 2 - the y-intercept would be -2)

9. First, find the x and y-intercepts. The y intercept is -3 You’d graph that at (0, -3). 0 = -1/2x - 3. -1/2x = 3. x = -6 so the x-intercept is at (-6, 0). If you only need to graph 2 points, then you can graph just those two points and draw a line between them.

To graph y=-1/2x + 3, start at the y-intercept and use the slope (-1/2) to find other points. Because your slope is -1/2, you’d go down 1 unit and then to the right 2 units. That would be your next point. If you wanted your line to go further up, go up one unit and then to the left 2 units. That would be your next point.

I am not sure what you need to do on 11 and 12

I think you should try 7, 8 and 10 on your own and let me know if you have any questions on them or if you are stuck on anything.
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