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Free_Kalibri [48]
3 years ago
9

Mr. Moran chose 10 different test scores out of 50, and they are shown below. For the following set of data, find the mean test

score, rounding to the nearest tenth (i.e. one decimal place)
{48, 36, 21, 19, 50, 50, 49, 44, 38, 40}
Mathematics
1 answer:
frozen [14]3 years ago
5 0

Answer:

39.5

Step-by-step explanation:

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3 years ago
In the United States, 35% of households own a 4K television. Suppose we take a random sample of 150 households. (a) Describe the
sattari [20]

Answer:

(a) The distribution of the sample proportion is Normal distribution.

(b) The probability that in this sample of 150 households that more than 50% own a 4K television is 0.00012.

Step-by-step explanation:

We are given that in the United States, 35% of households own a 4K television.

Suppose we take a random sample of 150 households.

<em>Let </em>\hat p<em> = sample proportion of households who own a 4K television.</em>

The z-score probability distribution for sample proportion is given by;

           Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

     p = population proportion of households own a 4K television = 35%

     n = sample of households = 150

(a) The distribution of the sample proportion is related to the Normal distribution.

(b) Probability that in this sample of 150 households more than 50% own a 4K television is given by = P( \hat p > 0.50)

    P( \hat p > 0.50) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{ 0.50-0.35}{\sqrt{\frac{0.50(1-0.50)}{150} } } ) = P(Z > 3.67) = 1 - P(Z \leq 3.67)

                                                                   = 1 - 0.99988 = 0.00012

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 3.67 in the z table which has an area of 0.99988.</em>

Therefore, probability that in this sample of 150 households more than 50% own a 4K television is 0.00012.

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