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mart [117]
2 years ago
8

Find the equation of a line parallel to 4x-y=-3 that contains the point (-1,-2). Write the equation in slope-intercept form.

Mathematics
1 answer:
ZanzabumX [31]2 years ago
5 0

Answer:

Step-by-step explanation:

-y = -4x - 3

y = 4x + 3

y + 2 = 4(x + 1)

y + 2 = 4x + 4

y = 4x + 2

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WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!
Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: a^2-b^2=(a+b)(a-b)

Given  x^2-16=0

Rewrite 16 as 4²

Therefore, a^2=x^2 and b^2=4^2

\implies a = \sqrt{x^2}=x

\implies b=\sqrt{4^2} =4

\implies x^2-16^2=(x+4)(x-4)

\implies (x+4)(x-4)=0

\implies (x+4)=0 \implies x=-4

\implies (x-4)=0 \implies x=4

<u>Method 2</u>

Given equation:

x^2-16=0

Add 16 to both sides:

\implies x^2-16+16=0 + 16

\implies x^2=16

Square root both sides:

\implies \sqrt{x^2}=\sqrt{16}

\implies x=\pm4

Therefore, x = -4, x = 4

6 0
2 years ago
Find this quotient. <br> -36.86 <br> ______<br> -3.8 <br> The quotient is:
VMariaS [17]

Answer:

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Step-by-step explanation:

First convert the numbers into whole numbers by multiplying both numbers by 100. Then divide the numbers by using long division.

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Translate and simplify the expression the sum of fifteen and a number plus twelve
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8 0
2 years ago
Read 2 more answers
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