Find the equation of a line parallel to 4x-y=-3 that contains the point (-1,-2). Write the equation in slope-intercept form.

Mathematics

1 answer:

ZanzabumX [31]2 years ago

5 0

Answer:

Step-by-step explanation:

-y = -4x - 3

y = 4x + 3

y + 2 = 4(x + 1)

y + 2 = 4x + 4

y = 4x + 2

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2 years ago

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Write an equation of the line that passes through (2, -3) and is perpendicular to the line y=-2x-3

Natalija [7]

Answer:

$y=\frac{1}{2} (x-2)-3$ or $y=\frac{1}{2} x-4$

Step-by-step explanation:

The perpendicular slope is the opposite-reciprocal of the original slope:

Perpendicular slope of -2 is $\frac{1}{2}$

Write the equation in point-slope form ( $y=a(x-h)+k$ ):

$y=\frac{1}{2} (x-2)-3$

Convert to slope-intercept form if needed:

$y=\frac{1}{2} x-1-3$

$y=\frac{1}{2} x-4$

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3 years ago

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Someone help me please and thank you!! ASAP :(

pantera1 [17]

<h3>Answer: Choice D) </h3>

Work Shown:

$(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\$