I did it on the calculator and the answer is 7.77777777778
The height of the isosceles triangle is 8.49 inches.
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How to find the height of the triangle?</h3>
Here we have a triangle such that two of the sides measure 9 inches, and the base measures 6 inches.
So this is an isosceles triangle.
We can divide the isosceles triangle into two smaller right triangles, such that the side that measures 9 inches is the hypotenuse, the base is 3 inches, and the height of the isosceles triangle is the other cathetus.
By Pythagorean's theorem, we can write:
(9in)^2 = (3 in)^2 + h^2
Where h is the height that we are trying to find.
Solving that for h we get:
h = √( (9 in)^2 - (3in)^2) = 8.49 inches.
We conclude that the height of the isosceles triangle is 8.49 inches.
If you want to learn more about triangles:
brainly.com/question/2217700
#SPJ1
42 - -84=-42
Hope this helps :)
452.16 = 3.1416 r^2
r^2 = 452.16 / 3.1416
r^2 = 143.93
r = 11.997
C = 2 (3.1416) (12) =75.38 m
I dont have paper with me but just solve 2(-2)^3+2 for the first one. The second one is -28 though