Answer: t1 = -34; t2 = -64; t3 = -94
d is the distance between numbers (d > 0)
we have:
t5 = t1 + 4d = -154
t9 = t1 + 8d = -274
we have the equations:
t1 + 4d = -154
t1 + 8d = -274
<=> t1 = -34
d = -30
with t1 = -34 and = -30 => t2 = -34 - 30 = -64
t3 = -64 - 30 = -94
Step-by-step explanation:
Answer:
The perimeter of a circle can be found by using the followinfg expression
P = 2*π*r
where
π = 3.14
r = radius of the circle = half the diameter of the circle
In this case, if we are given the radius, we use
P = 2*π*r
If we are given the diameter, we use
P = 2*π*(D/2) = π*D
1) 27in
radius = 27in
P = 2*(3.14)*(27 in) = 169.56 in
diameter = 27 in
P = (3.14)*(27 in) = 84.78 in
2) 79 in
radius = 79 in
P = 2*(3.14)*(79 in) = 496.12 in
diameter = 79 in
P = (3.14)*(79 in) = 248.06 in
3) 1809 in
radius = 1809 in
P = 2*(3.14)*(1809 in) = 11360.52 in
diameter = 1809 in
P = (3.14)*(1809 in) = 5680.26 in
4) 152 in
radius = 152 in
P = 2*(3.14)*(152 in) = 954.56 in
diameter = 152 in
P = (3.14)*(152 in) = 477.28 in
Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.
Num days late = 0.8 * 30=24
So Deborah was late 24 out of 30 working days. Would appreciate a brainliest
