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3 years ago

Evaluate each using the values given n-n-(n+n-m);use m=6,and n=-10

1 answer:

5 0

In order to evaluate the expression, certain order should be followed. We should start by evaluating terms in brackets, then move on to any multiplication or division and finally evaluate addition and subtraction.

In the given term, we will start by evaluating the term in brackets and then evaluate the subtraction outside the bracket.

It is also good to know the following (note the signs and the resulting operation):
2 + 2 = 4
2 - 2 = 0
2 + -2 = 2 - 2 = 0
-2 -2 = -4
-2 + -2 = -2 -2 = 4
-2 + 2 = 0

Now for the term we have:
<span> n-n-(n+n-m) where m = 6 and n = -10
Substituting in the expression, we will get:
-10 - -10 - (-10 + -10 - 6)
which can be written as:
-10 + 10 - (-10 - 10 - 6)
evaluating the term in brackets we get:
-10 + 10 - (-26)
which can be written as:
-10 + 10 + 26 = 0 + 26 = 26

Therefore, the final result is 26.</span>

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NEED HELP ASAPPPPPPPPP

Nookie1986 [14]

Answer:

A = 57°

B = 19°

C = 104°

Step-by-step explanation:

We have a triangle with 3 angles:

A, B, and C.

We know that:

"Angle A is 3 times larger than angle B"

We can write this as:

A = 3*B

"Angle C was 10° less than 6 times angle B"

This can be written as:

C = 6*B - 10°

And we also know that the sum of all interior angles of a triangle is 180°

Then we also have the equation:

A + B + C = 180°

So we have a system of 3 equations:

A = 3*B

C = 6*B - 10°

A + B + C = 180°

To solve this, the first step is to isolate one of the variables in one of the equations.

We can see that A is already isolated in the first one, so we can skip that step.

Now we need to replace A in the other equations, to get:

C = 6*B - 10°

(3*B) + B + C = 180°

Now we have a system of two equations.

Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:

3*B + B + (6*B - 10°) = 180°

Now we can solve this for angle B

4*B + 6*B - 10° = 180°

10*B - 10° = 180°

10*B = 180° + 10° = 190°

B = 190°/10 = 19°

Now that we know the measure of angle B, we can input this in the equations:

A = 3*B

C = 6*B - 10°

To find the measures of the other two angles:

A = 3*19° = 57°

C = 6*19° - 10° = 104°

5 0

3 years ago

What percent of 156 is 78

alina1380 [7]

50% is your answer hope i helped you

4 0

3 years ago

Given that g(x)=-X+2, find f(4)

vredina [299]

Answer:

See below.

Step-by-step explanation:

g(x) and f(4) refer to different functions.

Since we are not given f(x) is, we cannot answer the question.

4 0

3 years ago

HELP FAST GIVE A DECENT AMOUNT OF POINTS! FOR EASY!

laila [671]

Answer:

The value of angle is 56.9°

Step-by-step explanation:

First, you have to find the length of hypotenuse using Pythagoras' Theorem, c² = a² + b² :

${c}^{2} = {a}^{2} + {b}^{2}$

$let \: a = 8.25 \\ let \: b = 6.45$

${c}^{2} = {8.25}^{2} + {6.45}^{2}$

${c}^{2} = 68.0625 + 41.6025$

${c}^{2} = 109.665$

$c = \sqrt{109.665}$

$c = 10.47cm \: (4s.f)$

In order to find θ, you have to apply Sine Rule :

$\sin(θ) = \frac{opposite}{adjacent}$

$let \: oppo. = 8.77 \\ let \: hypo. = 10.47$

$\sin(θ) = \frac{8.77}{10.47}$

$θ = { \sin( \frac{8.77}{10.47} ) }^{ - 1}$

$θ = 56.9 \: (1d.p)$

4 0

3 years ago

Given: AB ∩ GF = O, E ∈ interior of ∠GOB, H ∈ interior of ∠AOF. Without changing the picture indicate:

sesenic [268]

Answer:

Step-by-step explanation:

Given that

AB n GF = O

E ∈ ∠GOB

H ∈ ∠AOF

The we can say, using similar angles or triangles, that

BF = AG

EG = AH

BG = FA

4 0

3 years ago