1. The remaing area of the yard will be found as follows:
Area of the yard
A1=length*width=10x*15x=150x^2 yd^2
area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2
The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2
2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2
Area of the field
A2=length×width
A2=3x×6x=18x^2
Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units
You are adding 9/3 each time
so 2/3, 11/3, 20/3, 29/3, 38/3, 47/3
hope this helps
Answer:
1/2
Step-by-step explanation:
Answer:
so is the deal on? or not?
