No answer is possible until we know the number that belongs after the words "... angular speed of ".
The resultant or the net force act on the object cannot be 0. it must have a value but the direction is opposite from the object move direction.
if the object move to the left, so the net force or the resultant is doing to the right
To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to
The ideal gas equation said us that,
PV = nRT
Here,
P = pressure
V = Volume
R = Gas ideal constant
T = Temperature
n = Amount of substance (at this case the mass)
Then
The amount of substance per volume is the density, then
Replacing with our values,
Finally the specific volume would be
Answer:
592000 J
Explanation:
We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:
1 Pa = 1 Kg/ms²
Therefore,
3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²
Next, we shall determine the workdone.
Workdone is given by the following equation:
Workdone (Wd) = pressure (P) × change in volume (ΔV)
Wd = PΔV
With the above formula, the work done can be obtained as follow:
Pressure (P) = 3.7×10⁵ Kg/ms²
Change in volume (ΔV) = 1.6 m³
Workdone (Wd) =?
Wd = PΔV
Wd = 3.7×10⁵ × 1.6
Wd = 592000 Kgm²/s²
Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:
1 Kgm²/s² = 1 J
Therefore,
592000 Kgm²/s² = 592000 J
Therefore, the Workdone is 592000 J.
Answer:
q = 7.542 x 10⁻⁷ C = 754.2 nC
Explanation:
The Coulomb's Law gives the magnitude of the force of attraction or repulsion between two charges:
F = kq₁q₂/r²
where,
F = Force of attraction or repulsion = 0.2 N
k = Coulomb's Constant = 9 x 10⁹ N m²/C²
r = distance between charges = 16 cm = 0.16 m
q₁ = magnitude of 1st charge
q₂ = magnitude of 2nd charge
Since, both charges are said to be equal here.
q₁ = q₂ = q
Therefore,
0.2 N = (9 x 10⁹ N m²/C²)q²/(0.16 m)²
(0.2 N)(0.16 m)²/(9 x 10⁹ N m²/C²) = q²
q = √(5.88 x 10⁻¹³ C²)
<u>q = 7.542 x 10⁻⁷ C = 754.2 nC</u>
