Answer:
AI = 0.019 A
Explanation:
The computation of the current change and the same compared to the staring is shown below;
I = v ÷ R
= 5v ÷ 81.0
I = 0.074 A
Now
I = v ÷ r
= 6v ÷ 81.0
I = 0.055A
Now
I = 0.074A - 0.055A
AI = 0.019 A
The same would be considered
By definition, the gain in PE (potential energy) is
ΔPE = m*g*h
Given:
mg = 40 N (Note that m*g = weight)
h = 5 m
ΔPE = (40 N)*(5 m) =200 J
Answer: 200 J
Answer:
- the Thevenin equivalent circuit for the battery is uploaded below
- the battery delivered 117 watts of power to the starter motor
Explanation:
Given the data in the equation
diagram of the Thevenin equivalent circuit for the battery is uploaded below.
Current I = 10 A
Voltage 1 = 12 V
voltage 2 = 11.7 v
R = (V1 - V2) / I
R = (12-11.7)/10
R = 0.3 / 10
R = 0.03Ω
Thevenin equivalent circuit
= V2 / I = 11.7 / 10
= 1.17Ω
so, power delivered to the starter motor will be;
p = (V2)² /
P = ( 11.7 V )² / 1.17Ω
p = 136.89 / 1.17
p = 117 watts
Therefore, the battery delivered 117 watts of power to the starter motor