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2 years ago

Write me What is 10/12 using simplest form

Mathematics

2 answers:

Serjik [45]2 years ago

8 0

Found it online hope that’s helps

Iteru [2.4K]2 years ago

5 0

Answer:

10/12=5/6.....

Step-by-step explanation:

Hope it helpz!!

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If we reject the null hypothesis in a test using analysis of variance, we are concluding that

Bond [772]

You would be concluding that <span>the populations from which our samples come are different. I hope this helps.</span>

7 0

3 years ago

Which number is in the ten-thousands place : 223.9087 Which number is in the thousands place: 223.9087 Which number is in the hu

zhuklara [117]

1st- 2
2nd- 9
3rd- 0
4th 8
Hope that helped

8 0

3 years ago

Wha is 3x+3y=-9 in standard to slope intercept form simplified, thank you!

Alona [7]

Answer

Step-by-step explanation:

The answer would be y=-x-3. 3x+3y=-9 is in standard form and you want it to be in y=mx=b form (slope-int) so subtract 3x by both sides. Now, you have 3y=-3x-9. Divide 3 to both sides, now you will get y=-x-3.

6 0

3 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

6 0

3 years ago

"Find the constants m and b in the linear function f(x) = mx + b so that f(2) = 10 and the straight line represented by f has sl

Ksju [112]

f(x) = mx + b m = slope = -5 f(2) = 10 = (-5)(2) + b b = 10 + 10 = 20 Ans. m=-5, b = 20

6 0

3 years ago