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SashulF [63]
3 years ago
8

.:$$:$;&4&4’xkekekenfnejeidndndj HELPPP

Mathematics
2 answers:
hjlf3 years ago
6 0
Yes, it does. Usne ksheen
nikklg [1K]3 years ago
5 0

Answer: Yes

Step-by-step explanation: You can test whether a graph is a function by checking to see if the same X value is used twice. You can also use the Vertical line test to check aswell. Research Vertical Line Test if you are clueless. But Yes, this is a function

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Write the equation ∣4−r/3∣=7 as two separate equations, and enter each equation in its own answer box below. Neither of your equ
Naddik [55]

Answer:

4 - r/3 = 7   and 4 - r/3 = -7

Step-by-step explanation:

absolute value equations get split into a positive equation and a negative equation

4 - r/3 = 7   and 4 - r/3 = -7


6 0
3 years ago
Write 8 x 8 x 8 x 8 using an exponent.
vredina [299]

Answer: 8^4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
(+12) - (-12) =<br><br><br><br><br>Resultado, porque, operación completa, 10 puntos
musickatia [10]
24 because the - cancel eachother out.
3 0
2 years ago
Write an exponential function y = abx for a graph that includes (–3, 16) and (–1, 4) f(x) = 2(0.5)x f(x) = 0.5(2)x f(x) = 4(0.3)
Arisa [49]

Answer: f(x)=2(0.5)^x

Step-by-step explanation:

Given, the exponential function y = ab^x for a graph that includes (–3, 16) and (–1, 4).

On putting these points, we will have

f(-3)=16=ab^{-3}\\\\ f(-1)=4=ab^{-1}

Now,

\dfrac{f(-3)}{f(-1)}=\dfrac{16}{4}=\dfrac{ab^{-3}}{ab^{-1}}\\\\\Rightarrow\ \dfrac{4}{1}=\dfrac{b^{-3}}{b^{-1}}\\\\\Rightarrow\ \dfrac{4}{1}=\dfrac{b}{b^3}=\dfrac{1}{b^2}\\\\\Rightarrow\ b^2=\dfrac{1}{4}\\\\\Rightarrow\ b=\pm\dfrac{1}{2}=\pm0.5

since the multiplicative factor cannot be negative, so b= 0.5.

At b= 0.5

4=a(0.5)^{-1}\\\\\Rightarrow\ 4=a(\dfrac{1}{2})^{-1}\\\\\Rightarrow\ 4=a(2)\\\\\Rightarrow \ a=2

So, the required function is f(x)=2(0.5)^x.

3 0
3 years ago
An encryption key is used to help decrypt messages. True or False. Explain why
vodomira [7]

Answer:

True!

Step-by-step explanation:

   

6 0
3 years ago
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