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3 years ago

What is the answer to 3x+8y+13x

Mathematics

2 answers:

vovikov84 [41]3 years ago

4 0

Collect the like terms
3x+13x=16x
16x+8y

amm18123 years ago

3 0

Simplifying
3x + 8y + 13x = 0

Reorder the terms:
3x + 13x + 8y = 0

Combine like terms: 3x + 13x = 16x
16x + 8y = 0

Solving
16x + 8y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8y' to each side of the equation.
16x + 8y + -8y = 0 + -8y

Combine like terms: 8y + -8y = 0
16x + 0 = 0 + -8y
16x = 0 + -8y
Remove the zero:
16x = -8y

Divide each side by '16'.
x = -0.5y

Simplifying
x = -0.5y

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5+4g+8=1 (g=-3;g =-1; g =2)

makkiz [27]

When g equals- 3 answer is 1

4 0

3 years ago

What is an equation of the line that passes through the points (-6, -2) and

den301095 [7]

Answer:

The equation of line is: $\mathbf{4x-3y=-18}$

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?

The equation of line in slope-intercept form is: $y=mx+b$

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=-6,y_1=-2, x_2=-3, y_2=2$

Putting values and finding slope

$Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}$

So, we get slope: $m=\frac{4}{3}$

Finding y-intercept

Using point (-6,-2) and slope $m=\frac{4}{3}$ we can find y-intercept

$y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6$

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope $m=\frac{4}{3}$ and y-intercept b = 6 is

$y=mx+b\\y=\frac{4}{3}x+6$

Now transforming in fully reduced form:

$y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18$

So, the equation of line is: $\mathbf{4x-3y=-18}$

6 0

2 years ago

The following list details the numbers of tickets sold for a talent show grade 9:22; grade 10:32; grade 11: 41; and grade 12:30.

Montano1993 [528]

Answer: C. domain: {9, 10, 11, 12); range: (22, 32, 41, 30)

Step-by-step explanation:

The data set is:

(9, 22)

(10,32)

(11, 41)

(12, 30).

In the usual notation, the number at the left is the input (belons to the domain) and the number in the right is the output (belongs to the range).

Then the domain would be:

{9, 10, 11, 12}

and the range:

{22, 32, 41, 30}

The correct option is C

7 0

3 years ago

WILL GIVE A BRAINLIEST PLEASE HELP!!!

kaheart [24]

A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank

In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).

a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)

7 0

3 years ago

Can someone please please help me on this algebra problem I’m stuck on answering the question?

Rudik [331]

Explanation:

Midline: it is a horizontal line where half of the function above it and half of the function is below it.

Amplitude: It means how far the function varies from the midline to the above and below.

Period: the distance between two consecutive maximum points (minimum points).

3) From the graph,

$\begin{gathered} \text{Midline}=\frac{Maximum\text{ point+ minimum point}}{2} \\ =\frac{3+(-1)}{2} \\ =\frac{3-1}{2} \\ =\frac{2}{2} \\ =1 \end{gathered}$

Answer: Midline=1

1) Amplitude

$\text{Amplitude =}2$

2) Periods

$\begin{gathered} \text{Period}=6 \\ \Rightarrow b=\frac{2\pi}{6} \end{gathered}$

4) The trigonometric equation is,

$\begin{gathered} y=a\cos (b(x-c))+d \\ a=\text{ amplitude} \\ b=\text{period} \\ c=\text{ phase shift} \\ d=\text{ vertical shift} \\ y=2\cos (\frac{2\pi}{6}x)+1 \end{gathered}$

Answer:

$y=2\cos (\frac{2\pi}{6}x)+1$

4 0

1 year ago